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2 years ago

I GIVE BRAINLILEST

Mathematics

1 answer:

stich3 [128]2 years ago

6 0

Answer:

96 kilograms

Step-by-step explanation:

32x3=96 just trust me I don'T know how to explain

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What is the value of x

borishaifa [10]

$x^2=4^2+4^2\\
x^2=2\cdot16\\
x^2=32\\
x=\sqrt{32}=4\sqrt2$

5 0

3 years ago

Gerardo works at an ice cream shop each flavor of ice cream is stored in a right cylindrical tub that measures approximately 9 i

Leokris [45]

Answer:

Volume left = 404.32 cubic inches

Step-by-step explanation:

volume of a cylinder = $\pi$ $r^{2}$ h

volume of ice cream in the cylindrical tub = $\frac{22}{7}$ x $5^{2}$ x 9

= $\frac{22}{7}$ x 25 x 9

= 707.1429

Volume of ice cream in the cylindrical tub is 707.14 cubic inches.

The ice cream scoop has a spherical volume, so that;

volume of a sphere = $\frac{4}{3}$ $\pi$ $r^{3}$

r = $\frac{2.5}{2}$

= $\frac{5}{4}$ inches

volume of the scoop = $\frac{4}{3}$ x $\frac{22}{7}$ x $(\frac{5}{4} )^{3}$

= $\frac{4}{3}$ x $\frac{22}{7}$ x $\frac{125}{64}$

= 8.1845

volume of the scoop is 8.19 cubic inches.

If he scoops 37 scoops,

volume of the 37 scoops = 37 x 8.1845

= 302.8265

volume of 37 scoops is 302.83 cubic inches.

Volume of ice cream left in the tub = 707.1429 - 302.8265

= 404.3164

Volume of ice cream left in the tub is 404.32 cubic inches.

7 0

3 years ago

Please solve ill give you brainliest

mina [271]

Answer:

Step-by-step explanation:

Download pdf

8 0

2 years ago

Read 2 more answers

Evaluate the expression, xz- y, if x=3,y=6, and z =7

avanturin [10]

3*7-6
21-6=15
15 is the answer

4 0

2 years ago

Scores on a test are normally distributed with a mean of 81.2 and a standard deviation of 3.6. What is the probability of a rand

Misha Larkins [42]

<u>Answer:</u>

The probability of a randomly selected student scoring in between 77.6 and 88.4 is 0.8185.

<u>Solution:</u>

Given, Scores on a test are normally distributed with a mean of 81.2

And a standard deviation of 3.6.

We have to find What is the probability of a randomly selected student scoring between 77.6 and 88.4?

For that we are going to subtract probability of getting more than 88.4 from probability of getting more than 77.6

Now probability of getting more than 88.4 = 1 - area of z – score of 88.4

$\mathrm{Now}, \mathrm{z}-\mathrm{score}=\frac{88.4-\mathrm{mean}}{\text {standard deviation}}=\frac{88.4-81.2}{3.6}=\frac{7.2}{3.6}=2$

So, probability of getting more than 88.4 = 1 – area of z- score(2)

= 1 – 0.9772 [using z table values]

= 0.0228.

Now probability of getting more than 77.6 = 1 - area of z – score of 77.6

$\mathrm{Now}, \mathrm{z}-\text { score }=\frac{77.6-\text { mean }}{\text { standard deviation }}=\frac{77.6-81.2}{3.6}=\frac{-3.6}{3.6}=-1$

So, probability of getting more than 77.6 = 1 – area of z- score(-1)

= 1 – 0.1587 [Using z table values]

= 0.8413

Now, probability of getting in between 77.6 and 88.4 = 0.8413 – 0.0228 = 0.8185

Hence, the probability of a randomly selected student getting in between 77.6 and 88.4 is 0.8185.

4 0

3 years ago