Answer:
y=t−1+ce
−t
where t=tanx.
Given, cos
2
x
dx
dy
+y=tanx
⇒
dx
dy
+ysec
2
x=tanxsec
2
x ....(1)
Here P=sec
2
x⇒∫PdP=∫sec
2
xdx=tanx
∴I.F.=e
tanx
Multiplying (1) by I.F. we get
e
tanx
dx
dy
+e
tanx
ysec
2
x=e
tanx
tanxsec
2
x
Integrating both sides, we get
ye
tanx
=∫e
tanx
.tanxsec
2
xdx
Put tanx=t⇒sec
2
xdx=dt
∴ye
t
=∫te
t
dt=e
t
(t−1)+c
⇒y=t−1+ce
−t
where t=tanx
Answer:
- 32, - 26, - 20, - 14
Step-by-step explanation:
To find the first 4 terms , substitute n = 1, 2, 3, 4 into the rule
a₁ = 6(1) - 38 = 6 - 38 = - 32
a₂ = 6(2) - 38 = 12 - 38 = - 26
a₃ = 6(3) - 38 = 18 - 38 = - 20
a₄ = 6(4) - 38 = 24 - 38 = - 14
It is simple
you do 45,600 divided by 22
which equals about 2,072.72
