When you divide by a fraction, flip the fraction over and change divide to multiply:
3/2 / 1/8 would become:
3/2 x 8/1
8/1 simplifies to 8
You get:
3/2 x 8 = 12
The answer is:
Three-halves times 8 = 12
Answer with Step-by-step explanation:
We are given that if sum of several numbers is odd
We have to prove that at least one of the number is itself odd.
Suppose, we have three numbers
a=6 , b=7,d=8
Sum of numbers=6+7+8=21=Odd number
We know that sum of two odd numbers is always an even number.
Sum of an odd number and an even number is always an odd number.
If we take even odd numbers then sum is always an even number and sum of odd odd numbers then the sum is always an odd number.
Sum of even numbers is always an even number.
Hence, there are atleast one numebr is odd then the sum of several number is odd.
Step-by-step explanation:
The given inequality is :
Solving RHS of the inequality:
Adding 6 both sides of the inequality
The attached figure shows the graph for the given inequality.
Answer:
The number is 5.
Step-by-step explanation:
The product of 5 and 4 more than a number = 9 times the number
Let the number be x;
5(4 + x) = 9x
20 + 5x = 9x
4x = 20
x = 20/5
x = 5.