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Harman [31]
2 years ago
12

Find the percentage error |sinθ - θ|/sin(θ)*100 this approximation introduces for an angle of 0. 020 radians.

Mathematics
1 answer:
Elza [17]2 years ago
8 0

Considering the given angle and the given formula, it is found that the percentage error for an angle of 0.02 radians is of 0.0067%.

<h3>What is the percentage angle for an angle?</h3>

For an angle \theta, it is given by the following formula:

P = 100\frac{|\sin{\theta} - \theta|}{\sin{\theta}}

In this problem, the angle is of \theta = 0.02, hence:

P = 100\frac{|\sin{0.02} - 0.02|}{\sin{0.02}}

P = 0.0067

The percentage error for an angle of 0.02 radians is of 0.0067%.

More can be learned about percent error at brainly.com/question/25224978

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Step-by-step explanation:

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The spread of a flu virus on a college campus is modeled by y= 5000/(1+4999e^-0.8t), where y is the number of students infected
Darina [25.2K]

Answer:

537 students

11 days

Step-by-step explanation:

       5000

y=  -----------------

    (1+4999e^-0.8t)

a)  after 8 days  means t =8


       5000

y=  -----------------

    (1+4999e^-0.8*8)

       5000

y=  -----------------

    (1+4999e^-6.4)

       5000

y=  -----------------

    (1+8.306)

       5000

y=  -----------------

    (9.306)

y =537.28

Rounding to the nearest student

y = 537 students


b)  1/2 the student population  means y =2500  (The 5000 is the student population)

             5000

2500=  -----------------

        (1+4999e^-0.8t)

Multiply each side by  (1+4999e^-0.8t)

2500 (1+4999e^-0.8t) = 5000

Divide each side by 2500

(1+4999e^-0.8t) = 5000/2500

(1+4999e^-0.8t) = 2

Subtract 1

(4999e^-0.8t) = 2-1

(4999e^-0.8t)=1

Divide by 4999

(4999/4999e^-0.8t)=1/4999

e^-0.8t=1/4999

Take the natural log of each side

ln(e^-0.8t)=ln(1/4999)

-.8t = ln(1/4999)

Divide by -.8

-.8/-8t = -1/.8 *ln(1/4999)

t = -1/.8 *ln(1/4999)

t≈10.6462

Rounding, it will take 11 days



7 0
3 years ago
Read 2 more answers
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