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blondinia [14]
3 years ago
15

Solve for x. 5 x − 19 ≤ 1 OR − 4 x + 3 < − 6

Mathematics
1 answer:
k0ka [10]3 years ago
4 0

5x - 19 \leqslant 1

change

\leqslant  \: to \:  =

given you

5x - 19 = 1

making x the subject by transferring the -19 to the right hand side of the equation

5x = 19 + 1

5x = 20

dividing through by 5

\frac{5x}{5}  =  \frac{20}{5}

x = 4

{{x:x  \leqslant 4}}

also given

- 4x + 3 < -  6

change the operation sign to =

- 4x + 3 =  - 6

- 4x =  - 6 - 3

- 4x =  - 9

dividing through by -4

\frac{ - 4x}{ - 4}  =  \frac{ - 9}{ - 4}

x =  \frac{9}{4}

so the truth set is

{x:x>9/4}.

The < sign changes to > because we divided by a negative number when solving for x

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