Answer:
The sample of students required to estimate the mean weekly earnings of students at one college is of size, 3458.
Step-by-step explanation:
The (1 - <em>α</em>)% confidence interval for population mean (<em>μ</em>) is:

The margin of error of a (1 - <em>α</em>)% confidence interval for population mean (<em>μ</em>) is:

The information provided is:
<em>σ</em> = $60
<em>MOE</em> = $2
The critical value of <em>z</em> for 95% confidence level is:

Compute the sample size as follows:

![n=[\frac{z_{\alpha/2}\times \sigma }{MOE}]^{2}](https://tex.z-dn.net/?f=n%3D%5B%5Cfrac%7Bz_%7B%5Calpha%2F2%7D%5Ctimes%20%5Csigma%20%7D%7BMOE%7D%5D%5E%7B2%7D)
![=[\frac{1.96\times 60}{2}]^{2}](https://tex.z-dn.net/?f=%3D%5B%5Cfrac%7B1.96%5Ctimes%2060%7D%7B2%7D%5D%5E%7B2%7D)

Thus, the sample of students required to estimate the mean weekly earnings of students at one college is of size, 3458.
Answer:
Let x = number of regular tickets sold.
Let y represent the number of student tickets sold.
12x+8y≤100012x+8y≤1000
x+y≥200x+y≥200
12x+8y≤20012x+8y≤200
x+y≤200x+y≤200
12x+8y≥1000
hope this helps
Step-by-step explanation:
Hello! For this question, you solve using order of operations, which you probably already have remembered as PEMDAS. Anytime a number is raised to the 0 power, that is equivalent to 1. 0.5^0 is 1. 250 * 1 is 250. x = 0 gives us the answer of 250. Now, let's solve for the number by the second power. 0.5² is 0.25. 250 * 0.25 is 62.5. x² gives us 62.5. Now, let's subtract the two numbers together. 250 - 62.5 is 187.5. Because the number is decreasing, the slope is negative, so the answer is -187.5. Your answer is correct.
Answer:
The store sold 2,210 footballs.
Step-by-step explanation: