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3 years ago

Which best explains whether a triangle with side lengths 5cm 13cm and 12 cm is a right triangle

Mathematics

2 answers:

VMariaS [17]3 years ago

7 0

Answer: the awnser is 0 jk its not

Step-by-step explanation:

i just want point repete dkmkmkrfnjrjnnfrfr

aniked [119]3 years ago

4 0

Answer:

Yes, it can make a right triangle.

Step-by-step explanation:

We can use the Pythagorean Theorem to determine if the sides make a right triangle.

$a^2+b^2=c^2$

We are given the side lengths: 5cm, 13cm, and 12 cm.

13cm is the longest, so it would be 'c'.

5cm and 12cm will be 'a' and 'b'.

Let 5 be 'a', 12 be 'b', and 13 be 'c':

$5^2+12^2=13^2\\\\\text{Solve the Exponents:}\\ \rightarrow 5^2=25\\\rightarrow 12^2=144\\\rightarrow 13^2=169\\\\25+144=169\\\boxed{169=169}$

5cm, 13cm, and 12 cm would make a right triangle. It satisfies the Pythagorean Theorem.

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Answer:

15/2

Step-by-step explanation:

My interpretation of your math expression is "2 1/2 divided by 1/3."

I prefer to write this as:

5 1

----- ÷ -----

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which is equivalent to:

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4 years ago

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2 years ago

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Answer:

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3 years ago

Harry is trying to solve the equation 0 = 2x2 − x − 6 using the quadratic formula. He has made an error in one of the steps belo

bija089 [108]

<h3><u>Given</u> - </h3>

➙ a quadratic equation in which Harry lagged due to an error made by him, 2x² - x - 6= 0

<h3><u>To solve</u> - </h3>

➙ the given quadratic equation.

<h3><u>Concept applied</u> - </h3>

➙ We will apply the quadratic formula as given in the question. So, let's study about quadratic equation first because we are supposed to apply the formula in equation.

What is quadratic equation?

➙ A quadratic equation in the variable x is an equation of the form ax² + bx + c = 0, where a, b, c are real numbers, a ≠ 0.

Now, what is quadratic formula?

➙The roots of a quadratic equation ax + bx + c = 0 are given by $\sf{\:\frac{-b \pm\: \sqrt {b ^ 2 - 4ac}}{2a}}$ provided b - 4ac ≥ 0.

<h3><u>Solution</u> - </h3>

here as per the given quadratic equation,

a = 2, b = -1 and c = -6

putting in the formula,

$\implies\sf{x=\frac{-(-1) \pm\: \sqrt {(-1)^2 - 4(2)(-6)}}{2(2)}}$

$\implies\sf{x=\frac{1 \pm\: \sqrt {1+48}}{4}}$

$\implies\sf{x=\frac{1 \pm\: \sqrt {49}}{4}}$

$\implies\sf{x=\frac{1 \pm\: 7}{4}}$

Solving one by one,

$\implies\sf{x=\frac{1 + \: 7}{4}}$

$\implies\sf{x=\frac{8}{4}}$

$\implies{\boxed{\bf{x=2}}}$

________________

$\implies\sf{x=\frac{1 - \: 7}{4}}$

$\implies\sf{x=\frac{-6}{4}}$

$\implies{\boxed{\bf{x=\frac{-3}{2}}}}$

________________________________

<em><u>Note</u> - Hey dear user!! You haven't provided the solution which was solved by Harry (A.T.Q). Please go through the solution as it will help you to find the error done by Harry.</em>

Hope it helps!! (:

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2 years ago

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schepotkina [342]

Answer:

The diameter of the circle O is <em>12 units</em>

Step-by-step explanation:

There is no data in the image provided. To better help you, I'm assuming we have an arbitrary value of

$BC=6\sqrt{2}$