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Dima020 [189]
2 years ago
6

Harry is trying to solve the equation 0 = 2x2 − x − 6 using the quadratic formula. He has made an error in one of the steps belo

w. Find the step where Harry went wrong. (1 point)
Mathematics
1 answer:
bija089 [108]2 years ago
4 0
<h3><u>Given</u> - </h3>

➙ a quadratic equation in which Harry lagged due to an error made by him, 2x² - x - 6= 0

<h3><u>To solve</u> - </h3>

➙ the given quadratic equation.

<h3><u>Concept applied</u> - </h3>

➙ We will apply the quadratic formula as given in the question. So, let's study about quadratic equation first because we are supposed to apply the formula in equation.

What is quadratic equation?

➙ A quadratic equation in the variable x is an equation of the form ax² + bx + c = 0, where a, b, c are real numbers, a ≠ 0.

Now, what is quadratic formula?

➙The roots of a quadratic equation ax + bx + c = 0 are given by \sf{\:\frac{-b \pm\: \sqrt {b ^ 2 - 4ac}}{2a}} provided b - 4ac ≥ 0.

<h3><u>Solution</u> - </h3>

here as per the given quadratic equation,

a = 2, b = -1 and c = -6

putting in the formula,

\implies\sf{x=\frac{-(-1) \pm\: \sqrt {(-1)^2 - 4(2)(-6)}}{2(2)}}

\implies\sf{x=\frac{1 \pm\: \sqrt {1+48}}{4}}

\implies\sf{x=\frac{1 \pm\: \sqrt {49}}{4}}

\implies\sf{x=\frac{1 \pm\: 7}{4}}

Solving one by one,

\implies\sf{x=\frac{1 + \: 7}{4}}

\implies\sf{x=\frac{8}{4}}

\implies{\boxed{\bf{x=2}}}

________________

\implies\sf{x=\frac{1 - \: 7}{4}}

\implies\sf{x=\frac{-6}{4}}

\implies{\boxed{\bf{x=\frac{-3}{2}}}}

________________________________

<em><u>Note</u> - Hey dear user!! You haven't provided the solution which was solved by Harry (A.T.Q). Please go through the solution as it will help you to find the error done by Harry.</em>

<em>________________________________</em>

Hope it helps!! (:

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Which expression is equivalent to the following complex fraction?
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Answer:

<h2>A. -2y+5x/3x-2y</h2>

Step-by-step explanation:

Given the complex fraction;

-\frac{2}{x} +\frac{5}{y} / \frac{3}{y} - \frac{2}{x} \\

First we will find the LCM of the numerator and the denominator as shown below;

\frac{-2y+5x}{xy} /\frac{3x-2y}{xy}

Then we divide both equation by multiplying the numerator by the reciprocal of the denominator as shown;

= \frac{-2y+5x}{xy} * \frac{xy}{3x-2y}  \\= \frac{-2y+5x}{3x-2y} \\

This gives the required answer

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Simplify.<br><br> [3 • (3 – 9)] + 9
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(9-27)+9

=-18+9

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first off, let's convert the mixed fractions, to "improper", and then subtract.

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4 0
3 years ago
HELP PLEASE!! I NEED HELP ASAP!
Alex73 [517]

Answer:

4. A

5. B

Step-by-step explanation:

4. I'll solve question four first:

The two marked points on the line are (-2, -3)&(2, 5). Using the formula to find slope(y2-y1/x2-x1), substitute in the points.

5--3/2--2 or 8/4;simplified to 2/1 or 2.

Now use point-slope form: y-y1 = m(x-x1)

y--3 = 2(x--2): Substitute in the values of y1, m, and x1.

y+3 = 2x + 4: Distribute.

y = 2x + 1: Subtract three from both sides.

5. Do the same for question 5.

The first point is (-4, 2), the second point is (4, -1).

-1-2/4--4; -3/8.

Now use point-slope form:

y-2 = -3/8x -12/8: Substitute in the values of x1, y1, m, and distribute the slope to the parentheses.

y = -3/8x + 1/2

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