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yaroslaw [1]
3 years ago
12

A technician is building a thick client workstation that would be used to run a database and wants to ensure the best protection

against errors. What type of memory would be best suited for this?
Computers and Technology
1 answer:
emmasim [6.3K]3 years ago
7 0

Answer: ECC memory

Explanation:Error-correcting code(ECC) memory is used for the detection as well as correction of the internal storage data in the operating system. It is the memory code that cannot tolerated any type of the corruption in the data storage.

The ECC memory is usually found in the fields like financial computing, scientific etc.It is a reliable memory and provides high protection.Thus the technician should put the ECC memory in the workstation.

You might be interested in
What is the decimal equivalent of 11BA?
allsm [11]

Answer:

To convert hexadecimal number 11BA to decimal, follow these two steps:

Start from one's place in 11BA : multiply ones place with 16^0, tens place with 16^1, hundreds place with 16^2 and so on from right to left

Add all the product we got from step 1 to get the decimal equivalent of 11BA.

Using the above steps, here is the work involved in the solution for converting 11BA to decimal number (Don't forget that we start from ones place to so on...)

Decimal equivalent of "A" = (A) 10 × 16^0 = 10

Decimal equivalent of "B" = (B) 11 × 16^1 = 176

Decimal equivalent of "1" = 1 × 16^2 = 256

Decimal equivalent of "1" = 1 × 16^3 = 4096

Decimal equivalent of "11BA" = 409625617610

11BA = 4538

Here is the final answer, The hexadecimal number 11BA converted to decimal is therefore equal to:

4538

4 0
2 years ago
1. Write a program that declares an array named alpha with 50 components of the type double. Initialize the array so that the fi
Aleksandr [31]

Answer:

Explanation:

1. Write a program that declares an array named alpha with 50 components of the type double. Initialize the array so that the first 25 components are equal to the square of the counter (or index) variable and the last 25 components are equal to three times the index variable.  

  double alpha[50];

   for (int i=0;i<25;i++)

   {

       alpha[i]=i*i;

       alpha[i+25]=(i+25)*3;

  }

2. Output the array so that exactly ten elements per line are printed.  

   for (int i=0;i<50;i++)

   {

       cout<<i+1<<". "<<alpha[i]<<" ";

       if (((i+1)%10)==0)

       {

           cout<<endl;

       }

   }

3. Run your program again, but this time change the code so that the array is filled with random numbers between 1 and 100.  

   double alpha[50];

   for (int i=0;i<50;i++)

   {

       alpha[i]=rand()%101;

   }

   for (int i=0;i<50;i++)

   {

       cout<<i+1<<". "<<alpha[i]<<" ";

       if (((i+1)%10)==0)

       {

           cout<<endl;

       }

   }

4. Write the code that computes and prints the average of elements of the array.  

   double alpha[50],temp=0;

   for (int i=0;i<50;i++)

   {

       alpha[i]=rand()%101;

       temp+=alpha[i];

   }

   cout<<"Average :"<<(temp/50);

5. Write the code that that prints out how many of the elements are EXACTLY equal to 100.

   double alpha[50],temp=0;

   for (int i=0;i<50;i++)

   {

       alpha[i]=rand()%101;

       if(alpha[i]==100)

       {

           temp++;

       }

   }

   cout<<"Elements Exacctly 100 :"<<temp;

Please note:  If you put  each of above code to the place below comment  it will run perfectly after compiling

#include <iostream>

using namespace std;

int main()

{

   // If you put  each of above code here it will run perfectly after compiling

   return 0;

}

8 0
3 years ago
1 punto
masya89 [10]

Answer:

Retailing.

Explanation:

La venta al por menor o retailing es el suministro de bienes físicos a los consumidores para uso personal, sea en pequeña o grandes cantidades, siempre que esté destinado a consumidores finales. Es un sector que consta de diferentes ramas (como la industria alimentaria, la industria de la moda, la industria del mobiliario para el hogar, etc.). El comercio minorista es el último eslabón de la cadena de suministro que va desde el fabricante hasta el consumidor.

4 0
3 years ago
Can you help me in this question
Amiraneli [1.4K]

Answer:

6 2 and 0

Explanation:

This algorithm doesn't work if the list is not ordered ascending.

In this example it is not, and indeed the item "1" is never found.

first cycle: first=0, last=12 so midpoint=6

second cycle: first=0, last=5 so midpoint=2

last cycle: first=0, last=1 so midpoint=0

then last is assigned -1 so the while statement is no longer true.

7 0
3 years ago
c++ Write a program that reads a list of words. Then, the program outputs those words and their frequencies. The input begins wi
Margaret [11]

Answer:

The following are the program in the C++ Programming Language:

#include <iostream> //header file

#include <string>  //header file

#include <vector>  //header file

//name space

using namespace std;

//main function

int main() {

  vector<string> word; //set variable

  vector<int> c;  //set variable

  int s, counts = 0; //set variable

  string strng;  //set variable

  cout<<"Enter the size of string: "; //print message

  cin >> s; //get input

  cout<<"Enter the string: "; //print message

  for(int i = 0; i < s; ++i) {  //set for loop

     cin >> strng; //get input

     word.push_back(strng);

  }

  for(int i = 0; i < s; ++i) { //set for loop

         counts = 0;

         for(int j = 0;j<word.size();j++){ //set for loop

       if(word[j] == word[i]){ //set if statement

          counts++; //increament in counts

       }        

     }

      c.push_back(counts);

  }

  for(int i = 0; i < s; ++i) {

      cout << word[i] << " " << c[i] << endl;//print result

  }

  return 0;

}

<u>Output</u>:

Enter the size of string: 2

Enter the string: hello  sir

hello 1

sir 1

Explanation:

Here, we define three header files <iostream>, <String>, <vector> and namespace "std" after that we define main() method inside it.

  • Then, we set two vector type variables first one is string variable "word" and the second one is integer variable "c".
  • Then we set two integer variable "s" and "counts" and variable "counts" assign to 0.
  • Then, we get input from the user in variable "s" for the length of the loop.
  • Then, we set for the loop inside it, we get input in the variable "strng" from the user.
  • Then, we set the for loop for count the string repetition if any word comes again in the string then the value of count will increase.
  • Finally, we set for a loop to print the result.
4 0
3 years ago
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