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IJ=x-4
JK=5x+12
IK=9x-19
IJ+JK=IK
(x-4)+(5x+12)=(9x-19)
x-4+5x+12=9x-19
6x+8=9x-19
6x+8-6x+19=9x-19-6x+19
27=3x
3x=27
3x/3=27/3
x=9
IJ=x-4=9-4→IJ=5
JK=5x+12=5(9)+12=45+12→JK=57
IK=9x-19=9(9)-19=81-19→IK=62
Answer: Option B. IJ=5, JK=57, IK=62
Answer:
The slope is 3/5.
Step-by-step explanation:
I am assuming you mean
10x + 6y = 84
6y = -10x + 84
y = -5/3 x + 14.
So the slope of this line is -5/3 and the slope of a line perpendicular to it is
-1 / -5/3 = 3/5.
Answer:
Step-by-step explanation:
D is the right answer because g is midpoint of ah and e is midpoint of ab and eg is parallel to bh so eg equals half bh
