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2 years ago

I need help with this. I don’t understand it. Please help.

Mathematics

2 answers:

Y_Kistochka [10]2 years ago

7 0

Step-by-step explanation:

<h2>please mark me as brainlist please I 2731 ans in simplified </h2>

Akimi4 [234]2 years ago

6 0

Answer:

98 $\pi$ /3

Step-by-step explanation:

The shaded area of the circle is 1/6 of the area of a circle.

The area of a circle is ( $\pi$ *r^2)/2

We are given that the diameter is 28 m. So the radius(r) is 14 m.

The area of the circle is ( $\pi$ *(14)^2)/2 = 196 $\pi$ .

Since the shaded area is 1/6 of the circle,

196 $\pi$ /6 = 98 $\pi$ /3.

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viva [34]

we know that

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In this problem

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substitute given values in the formula

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1 year ago

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QveST [7]

Answer:

We conclude that the mean nicotine content is less than 31.7 milligrams for this brand of cigarette.

Step-by-step explanation:

We are given the following in the question:

Population mean, μ = 31.7 milligrams

Sample mean, $\bar{x}$ = 28.5 milligrams

Sample size, n = 9

Alpha, α = 0.05

Sample standard deviation, s = 2.8 milligrams

First, we design the null and the alternate hypothesis

$H_{0}: \mu = 31.7\text{ milligrams}\\H_A: \mu < 31.7\text{ milligrams}$

We use One-tailed t test to perform this hypothesis.

Formula:

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Putting all the values, we have

$t_{stat} = \displaystyle\frac{28.5 - 31.7}{\frac{2.8}{\sqrt{9}} } = -3.429$

Now, $t_{critical} \text{ at 0.05 level of significance, 8 degree of freedom } = -1.860$

Since,

$t_{stat} < t_{critical}$

We fail to accept the null hypothesis and accept the alternate hypothesis. We conclude that the mean nicotine content is less than 31.7 milligrams for this brand of cigarette.

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3 years ago

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3 years ago

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3 years ago

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