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3 years ago

REALLY NEED HELP! PLEASE

Mathematics

2 answers:

Soloha48 [4]3 years ago

5 0

D is the right answer because g is midpoint of ah and e is midpoint of ab and eg is parallel to bh so eg equals half bh

Virty [35]3 years ago

3 0

Answer: The correct option is d, i.e., Segment EG is half the length of segment BH.

Explanation:

It is given that the triangle ABC with medians FA, BD, and CE. Segment FA is extended to H in such a way that segment GH is congruent to segment AG.

Since FA, BD, and CE are median it means the points D,E,F are the midoint of the line AC, AB, BC respectively.

It is also given that the line segment GH is congruent to segment AG. It means the point G is the mid point of the line segment AH.

In trianle ABH the line EG is joining the midpoint of AD and AH. So by using midpoint theorem of triangle we can say that the line EG and BH are parallel lines and the length of EG is half of the length of BH.

Therefre option d is correct.

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3 years ago

Find the mean of the data summarized in the given frequency distribution. Compare the computed mean to the actual mean of 47.3 m

Marta_Voda [28]

Answer:

$\bar X = \frac{2276}{48}=47.417$

If we compare this value with the 47.3 proposed we have the following error

$Error = \frac{|Actual-real|}{real}*100 = \frac{|47.417-47.3|}{47.3}*100 =0.247\%$

The computed mean is close to the actual mean because the difference between the means is less than 5%.

Step-by-step explanation:

Assuming the following dataset:

Speed 42-45 46-49 50-53 54-57 58-61

Freq. 21 15 6 4 2

And we are interested in find the mean, since we have grouped data the formula for the mean is given by:

$\bar X = \frac{\sum_{i=1}^n x_i f_i}{\sum_{i=1}^n f_i}$

And is useful construct a table like this one:

Speed Freq Midpoint Freq*Midpoint

42-45 21 43.5 913.5

46-49 15 47.5 712.5

50-53 6 51.5 309

54-57 4 55.5 222

58-61 2 59.5 119

Total 48 2276

And the mean is given by:

$\bar X = \frac{2276}{48}=47.417$

If we compare this value with the 47.3 proposed we have the following error

$Error = \frac{|Actual-real|}{real}*100 = \frac{|47.417-47.3|}{47.3}*100 =0.247\%$

The computed mean is close to the actual mean because the difference between the means is less than 5%.

6 0

3 years ago

A geometric sequence is defined recursively by an=12a(n-1). The first term of the sequence is 0.001. Which of the following is t

Talja [164]

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6 0

3 years ago

Note: Enter your answer and show all the steps that you use to solve this problem in the space provided.

nika2105 [10]

Step-by-step explanation:

13 + 22 = 35 degree change. 10-3 = 7. 35/7 = 5 degrees per hour.

4 0

3 years ago

Which statement(s) is (are) correct?

Anna71 [15]

Answer:

<em>statements 3 and 4 are correct.</em>

Step-by-step explanation:

(1)

The probability of choosing cured pasta and bear= probability that the card is king.

Hence, The probability of choosing cured pasta and bear= $\dfrac{4}{52}=\dfrac{1}{13}$

Probability of choosing baked cucumber and lime mutton=probability that the card is 3.

as there are 4 cards that are '3'.

Hence Probability of choosing baked cucumber and lime mutton= $\dfrac{4}{52}=\dfrac{1}{13}$

as both the probabilities are equal.

Hence statement 1 is incorrect.

(2)

The probability of choosing gooseberry & passion fruit cheesecake= Probability taht the card is ace.

as there are 4 cards which are ace out of 52 cards.

Hence, The probability of choosing gooseberry & passion fruit cheesecake= $\dfrac{4}{52}=\dfrac{1}{13}$

probability of choosing poached fennel & lemon alligator=Probability that the card is a face card.

As there are 12 face cards out of 52 cards.

Hence, probability of choosing poached fennel & lemon alligator= $\dfrac{12}{52}=\dfrac{3}{13}$

Hence, the probability of choosing gooseberry and passion fruit cheesecake is smaller than the probability of choosing poached fennel & lemon alligator.

Hence statement 2 is false.

(3)

The probability of choosing a praline wafer=probability that the card is a diamond.

as there are 13 diamond cards out of 52 cards.

The probability of choosing a praline wafer= $\dfrac{13}{52}=\dfrac{1}{4}$

the probability of choosing poached fennel & lemon alligator=Probability that the card is a face card.

As there are 12 face cards out of 52 cards.

Hence, probability of choosing poached fennel & lemon alligator= $\dfrac{12}{52}=\dfrac{3}{13}$

Hence, The probability of choosing a praline wafer is greater than the probability of choosing poached fennel & lemon alligator.

Hence statement 3 is correct.

(4)

The probability of choosing pressure-cooked mushroom & garlic chicken =probability that the card is red.

As there are 26 red cards out of 52 cards.

Hence,

The probability of choosing pressure-cooked mushroom & garlic chicken = $\dfrac{26}{52}=\dfrac{1}{2}$

probability of choosing an oven-baked apple & lavender calzone =probability that the card is black.

As there are 26 red cards out of 52 cards.

Hence, probability of choosing an oven-baked apple & lavender calzone= $\dfrac{26}{52}=\dfrac{1}{2}$

Hence, The probability of choosing pressure-cooked mushroom & garlic chicken and the probability of choosing an oven-baked apple & lavender calzone are the same.

Hence statement 4 is true.

(5)

The probability of choosing pressure-cooked mushroom & garlic chicken =probability that the card is red.

As there are 26 red cards out of 52 cards.

Hence,

The probability of choosing pressure-cooked mushroom & garlic chicken = $\dfrac{26}{52}=\dfrac{1}{2}$

the probability of choosing a praline wafer=probability that the card is a diamond.

as there are 13 diamond cards out of 52 cards.

The probability of choosing a praline wafer= $\dfrac{13}{52}=\dfrac{1}{4}$

Hence, the probability of choosing pressure-cooked mushroom & garlic chicken and the probability of choosing a praline wafer are not same.

Hence, statement 5 is not correct.

6 0

4 years ago