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3 years ago

REALLY NEED HELP! PLEASE

Mathematics

2 answers:

Soloha48 [4]3 years ago

5 0

D is the right answer because g is midpoint of ah and e is midpoint of ab and eg is parallel to bh so eg equals half bh

Virty [35]3 years ago

3 0

Answer: The correct option is d, i.e., Segment EG is half the length of segment BH.

Explanation:

It is given that the triangle ABC with medians FA, BD, and CE. Segment FA is extended to H in such a way that segment GH is congruent to segment AG.

Since FA, BD, and CE are median it means the points D,E,F are the midoint of the line AC, AB, BC respectively.

It is also given that the line segment GH is congruent to segment AG. It means the point G is the mid point of the line segment AH.

In trianle ABH the line EG is joining the midpoint of AD and AH. So by using midpoint theorem of triangle we can say that the line EG and BH are parallel lines and the length of EG is half of the length of BH.

Therefre option d is correct.

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3 years ago

Gavin rolls a fair dice 48 times.<br> How many times would Gavin expect to roll an even number?

pantera1 [17]

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Step-by-step explanation:

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2 years ago

A box contains different colored paper clips. The probability of drawing two red paper clips from the box without replacement is

ivann1987 [24]

Answer: 5/14 which is choice B

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How I got this answer:

Define the following events

A = event of picking a red paper clip on the first selection

B = event of picking a red paper clip on the second drawing

Replacement is not made.

Now onto the probabilities for each

P(A) = 2/5 = 0.4 is given to us as this is simply the probability of picking red on the first try

P(A and B) = probability of both events A and B happeing simultaneously = 1/7

P(B|A) = probability event B occurs, given event A has occured

P(B|A) = probability of selecting red on second selection, given first selection is red (no replacement)

P(B|A) = P(A and B)/P(A)

P(B|A) = (1/7) / (2/5)

P(B|A) = (1/7) * (5/2)

P(B|A) = (1*5)/(7*2)

P(B|A) = 5/14

So if event A happens, then the chances of event B happening is 5/14

------------------

A more concrete example:

If we had 15 paperclips, and 6 of them were red, then

P(A) = (# of red)/(# total) = 6/15 = 2/5

P(B|A) = (# of red left)/(# total left) = (6-1)/(15-1) = 5/14

P(A and B) = P(A)*P(B|A) = (2/5)*(5/14) = 10/70 = 1/7

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4 years ago

Read 2 more answers