Check the picture below.
notice the alternate interior angles in the picture.
![\bf tan(68^o)=\cfrac{\stackrel{opposite}{1.5}}{\stackrel{adjacent}{x}}\implies x=\cfrac{1.5}{tan(68^o)}\implies x\approx 0.61 \\\\[-0.35em] ~\dotfill\\\\ tan(56^o)=\cfrac{\stackrel{opposite}{1.5}}{\stackrel{adjacent}{w}}\implies w=\cfrac{1.5}{tan(56^o)}\implies w\approx 1.01 \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ ~\hfill \stackrel{\textit{width of the crater}}{x+w\implies 1.62}~\hfill](https://tex.z-dn.net/?f=%5Cbf%20tan%2868%5Eo%29%3D%5Ccfrac%7B%5Cstackrel%7Bopposite%7D%7B1.5%7D%7D%7B%5Cstackrel%7Badjacent%7D%7Bx%7D%7D%5Cimplies%20x%3D%5Ccfrac%7B1.5%7D%7Btan%2868%5Eo%29%7D%5Cimplies%20x%5Capprox%200.61%20%5C%5C%5C%5C%5B-0.35em%5D%20~%5Cdotfill%5C%5C%5C%5C%20tan%2856%5Eo%29%3D%5Ccfrac%7B%5Cstackrel%7Bopposite%7D%7B1.5%7D%7D%7B%5Cstackrel%7Badjacent%7D%7Bw%7D%7D%5Cimplies%20w%3D%5Ccfrac%7B1.5%7D%7Btan%2856%5Eo%29%7D%5Cimplies%20w%5Capprox%201.01%20%5C%5C%5C%5C%5B-0.35em%5D%20%5Crule%7B34em%7D%7B0.25pt%7D%5C%5C%5C%5C%20~%5Chfill%20%5Cstackrel%7B%5Ctextit%7Bwidth%20of%20the%20crater%7D%7D%7Bx%2Bw%5Cimplies%201.62%7D~%5Chfill)
A. In part 1, the bus drives pretty linearly. In part 2, the bus is at a stop. In part 3, the bus drives much faster, as the slope is much larger. In part 4, the bus is at a stop. In part 5, the bus comes back to its starting point.
B. The bus is increasing in parts 1 and 3, decreasing in part 5, and at a constant at parts 2 and 4.
C. The graph is non-linear, as the slope is not at a constant.
Hope this helps
Answer:
1:3
Step-by-step explanation:
Divide both of them by 3
Answer:
-37/99 is the simplest form. Hope this helps.