Question

The function Q(t)=Qoe^kt May be used to model radioactive decay. Q representing the quantity remaining after t years; k is the decay constant. What is the decay constant for plutonium -240 if it's half-life is 6,300 years?

Answer 1

Answer:

A. -[ln(0.5)/6,300]

Step-by-step explanation:

Done on apex, it is correct.

Answer 2

Answer : The value of decay constant is, $1.1\times 10^{-4}\text{ years}^{-1}$

Explanation :

Half-life of plutonium-240 = 6300 years

The expression used to calculate the rate constant is:

$k=\frac{0.693}{t_{1/2}}$

where,

k = decay constant

$t_{1/2}$ = half-life

Now put all the given values in the above formula, we get:

$k=\frac{0.693}{6300\text{ years}}$

$k=1.1\times 10^{-4}\text{ years}^{-1}$

Therefore, the value of decay constant is, $1.1\times 10^{-4}\text{ years}^{-1}$