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1 year ago

Solve for b a equals A=3(b + C)

Mathematics

1 answer:

Scrat [10]1 year ago

8 0

Answer: Correct option is A)

It is given that a:(b+c)=1:3 and c:(a+b)=5:7 and we solve these expressions

Step-by-step explanation:

b+c

⇒3a=b+c

⇒3a−b=c....(1)

a+b

⇒7c=5(a+b)

⇒7c=5a+5b....(2)

Multiplying the first equation by 7 we get:

7(3a−b)=7c

⇒7c=21a−7b....(3)

Now, subtracting equation 2 from equation 3, we have:

7c−7c=(21a−7b)−(5a+5b)

⇒0=21a−7b−5a−5b

⇒16a=12b

⇒b=

16a

⇒b=

Substituting the value of b in equation 1:

3a−

⇒c=

−

⇒c=

9a−4a

⇒c=

Now, lets find the value of b:(a+c) as shown below:

a+c

=1:2

hence, b:(a+c)=1:2.

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Divide 12x 4 y 4 by 3x 2 y. A. 4x 6y 5 B. 4x 2y 3 C. 9x 6 D. 9x 2y 3

andrew-mc [135]

Answer:

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Step-by-step explanation:

Consider an element $a\neq 0$

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Here, m and n are exponents and a is a base. Exponent refers to the no. of times a term is multiplied by itself. Another word for exponents is powers.

Other Properties of exponents:

$a^m\times a^n=a^{m+n}\\a^0=1\\\left ( a^m \right )^n=a^{mn}$

Here, we are required to divide $12x^4y^4$ by $3x^2y$ .

Consider $\frac{12x^4y^4}{3x^2y}$

We will solve $\frac{12}{3}\,,\,\frac{x^4}{x^2}\,,\,\frac{y^4}{y}$ separately.

Here,

$\frac{12}{3}=4\\\frac{x^4}{x^2}=x^{4-2}=x^2\\\frac{y^4}{y}=y^3$

So, $\frac{12x^4y^4}{3x^2y}=4x^2y^3$

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2 years ago

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Completely random design is used in this experiment.

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To learn more about Completely random design link is here

brainly.com/question/17128981

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stealth61 [152]

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Check the picture below.

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