Question

A function f(x) is graphed.

Answer 1

Answer:

Point-Slope form: The equation of line is given by:

$y-y_1=m(x-x_1)$              ......[1]

where m is the slope and $(x_1,y_1)$ is the point on the line.

From the given graph:

Consider two points i.e,

$(0, 1)$ and (-0.5, 0)

Calculate slope:

Formula for slope is given by;

$\text{Slope}(m) = \frac{y_2-y_1}{x_2-x_1}$

Substitute the given values we have;

$m = \frac{0-1}{-0.5-0} = \frac{-1}{-0.5} = \frac{10}{5} =2$

Now, substitute the value of m = 2 and (0, 1) in equation [1] we have;

$y-1 = 2(x-0)$

y-1 = 2x

Add 1 to both sides we get;

y = 2x+1

On comparing equation y = 2x+1 with the slope intercept form of a line (i.e, y = mx+b) then we have;

slope(m) = 2

y-intercept(b) = 1

therefore, the slope of the function:

m = 2

y-intercept(b) = 1

and the equation represents the graph: y = 2x+1

Answer 2

Answer:

m = 2

b = 1

y = 2x + 1

Step-by-step explanation:

Took test on ed thank me later :)