Question 1)
Given
The expression is 5xy
To determine
Find the value of 5xy if x = 2 and y = 3
5xy
substitute x = 2 and y = 3
5xy = 5(2)(3)
= 5(6)
= 30
Therefore, the value of 5xy = 30 if x = 2 and y = 3.
<em>Note: your remaining questions are not mentioned. But, the procedure may remain the same. Hopefully, your concept will be cleared anyway.</em>
Answer:Given that the graph shows tha the functión at x = 0 is below the y-axis, the constant term of the function has to be negative. This leaves us two possibilities:
y = 8x^2 + 2x - 5 and y = 2x^2 + 8x - 5
To try to discard one of them, let us use the vertex, which is at x = -2.
With y = 8x^2 + 2x - 5, you get y = 8(-2)^2 + 2(-2) - 5 = 32 - 4 - 5 = 23 , which is not the y-coordinate of the vertex of the curve of the graph.
Test the other equation, y = 2x^2 + 8x - 5 = 2(-2)^2 + 8(-2) - 5 = 8 - 16 - 5 = -13, which is exactly the y-coordinate of the function graphed.
Step-by-step explanation:
Would this work? Hope it helps
The answer is 22.5 so the reminder will be 1/2 or .5
Answer:
a = 0, b = 3
Step-by-step explanation:
3a + b = 3
b = - 3a +3
2a - 5b = - 15
2a - 5(-3a + 3) = - 15
2a + 15a - 15 = - 15
17a = 0
a = 0
b = -3a +3 = - 3 *0 +3 = 3
