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yulyashka [42]
3 years ago
12

a restaurant offers a lunch special in which a customer can select from one of the 7 appetizers, one of the 10 entrees, and one

of the 6 desserts. How many different lunch specials are possible?
Mathematics
1 answer:
Amiraneli [1.4K]3 years ago
6 0

Answer:

420

Step-by-step explanation:

Each of the 7 appetizers can be paired with one of 10 entrees, and each entree can be paired with one of 6 desserts.  So the number of combinations is:

7 × 10 × 6 = 420

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skelet666 [1.2K]

<em>Hi there!</em>

<em>~</em>

<em></em>(2a^2b+3ab^2-b^3)-(4b^3-3ab^2-6a^2b)<em></em>

<em>Distribute the Negative Sign:</em>

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<em>Combine Like Terms:</em>

<em></em>= 2a^2 b + 3ab^2 - b^3 + -4ab^3 + 3ab^2 + 6a^2 b\\= (2a^2 b + 6a^2 b) + ( 3ab^2 + 3ab^2) + (-b^3 + -4b^3) \\= 8a^2 b + 6ab^2 + -5b^3<em></em>

<em>Answer : </em>8a^2 b + 6ab^2 + -5b^3<em></em>

<em>Hope this helped you!</em>

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