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Ira Lisetskai [31]
3 years ago
6

What expression is equivalent to 24+30

Mathematics
1 answer:
worty [1.4K]3 years ago
6 0
1) 2(30x-24)
    60x-48
2) 3(20x-16)
    60x-48
3) 4(15x-12)
    60x-48
Simplify
60x-48
12(5x-4)
Answer: 12(5x-4)
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A Statistics professor has observed that for several years students score an average of 106 points out of 150 on the semester ex
tekilochka [14]

Answer:

Step-by-step explanation:

We would set up the hypothesis test. This is a test of a single population mean since we are dealing with mean

For the null hypothesis,

µ = 106

For the alternative hypothesis,

µ > 106

It is a right tailed test because of >.

Since no population standard deviation is given, the distribution is a student's t.

Since n = 241,

Degrees of freedom, df = n - 1 = 241 - 1 = 240

t = (x - µ)/(s/√n)

Where

x = sample mean = 109

µ = population mean = 106

s = samples standard deviation = 8.3

a) test statistic, t = (109 - 106)/(8.3/√241) = 5.61

We would determine the p value using the t test calculator. It becomes

p = 0.00001

Since alpha, 0.05 > than the p value, 0.00001, then we would reject the null hypothesis. Therefore, At a 5% level of significance, this improvement seem to be practically​significant.

b) Confidence interval is written in the form,

(Sample mean - margin of error, sample mean + margin of error)

The sample mean, x is the point estimate for the population mean.

Margin of error = z × s/√n

Where

s = sample standard deviation

n = number of samples

From the information given, the population standard deviation is unknown, hence, we would use the t distribution to find the z score

df = 240

Since confidence level = 95% = 0.95, α = 1 - CL = 1 – 0.95 = 0.05

α/2 = 0.05/2 = 0.025

the area to the right of z0.025 is 0.025 and the area to the left of z0.025 is 1 - 0.025 = 0.975

Looking at the t distribution table,

z = 1.6512

Margin of error = 1.6512 × 8.3/√241

= 0.88

Confidence interval = 109 ± 0.88

7 0
3 years ago
Find the flow rate through a tube of radius 6 cm, assuming that the velocity of fluid particles at a distance r cm from the cent
vaieri [72.5K]

Answer:

791.68 cm/s

Step-by-step explanation:

The volume flow rate can be interpreted as the integral of fluid velocity over area

\dot{V} = \int\limits^6_0 {v(r) 2\pi r} \, dr\\\dot{V} = 2\pi\int\limits^6_0 {(25-r^2)r} \, dr\\\dot{V} = 2\pi\int\limits^6_0 {25r-r^3} \, dr\\\\\dot{V} = 2\pi[12.5r^2 - r^4/4]_0^6\\\dot{V} = 2\pi(12.5*6^2 - 6^4/4 - 12.5*0 - 0)\\\dot{V} = 2\pi*126 = 791.68 cm/s

7 0
3 years ago
What grade level is a score of 235 in maps math I am really wanting to know
igomit [66]

Answer: It should be an 8th grade level

(sorry if i'm wrong)

:(

6 0
3 years ago
Math Help???????????
RUDIKE [14]

Answer:

A,C,D,E

Step-by-step explanation:

When plotting to use the form

(X,Y) aka (horizontal, vertical)

7 0
3 years ago
Read 2 more answers
69) Half-way to the center of a planet of uniform density, your weight compared to that at the surface would be :
mel-nik [20]

Answer:

One- half

Step-by-step explanation:

Since the density is uniform  

Mass of the sphere = [(4/3) π r^3] d

where d is the uniform density.

Mass of the sphere = [(4/3) π d] r^3 = k r^3

where k = [(4/3) π d] is a constant  

Weight = mg = G m M / r^2 = G m [k r^3] /r^2 = G m k r

Using Gauss’ law for gravitation,

Half way to the center of a planet the weight is only due to the inner sphere and the outer sphere does not contribute to his weight,  

Inside his weight is mg’ = (G m k  r) /2   = mg/2  

Answer is one-half.

7 0
3 years ago
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