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Vaselesa [24]
3 years ago
12

Identify the slope and y-intercept of this equation and then show the steps to convert to standard form

Mathematics
1 answer:
kirill [66]3 years ago
5 0

The slope is the factor in front of x, so slope is 9.

The y intercept is 7 (that's the point of cross the y axis, where x=0)

There are multiple definitions of "standard form" for lines, so here are the two i can think of:

9x - y = -7    (the implicit function form)

or

y-7 = 9*(x-0)  (the point-slope form)

Lmk if you have questions.

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A rectangular ballroom is being carpeted. The room measures 30 feet by 25 feet. If the carpet costs $3.00 per square foot, then
Taya2010 [7]

Answer:

$2250

Step-by-step explanation:

30 x 25 = 750 -> area

750 x 3= 2250

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The area of a rectangular rug is 16 square feet. If the length of the rug measures 6 feet long, what is the width?
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What is the approximate value of square root 7 to the nearest tenth? helppppp PLEASEE!!
vlada-n [284]

Square root 7 to the nearest tenth is 2.60

Step-by-step explanation:

To find square root of 7, you write;

√7=2.645

To the nearest tenth you check the hundredth value which is 4

√7=2.645 = 2.60

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3 years ago
Hello can some one please help me
Archy [21]

Answer:

216

Step-by-step explanation:

Remember that a^{b}=a*a*a*a*... b~~times.

So, 6^3=6*6*6=(6*6)*6=36*6=\boxed{216}

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Management at Webster Chemical Company is concerned as to whether caulking tubes are being properly capped. If a significant pro
marta [7]

Answer:

UCL = 0.078

LCL = 0

Step-by-step explanation:

<em>Poorly formatted question (see attachment)</em>

From the attachment, we have:

n = 135 --- the sample size

Samples = 20 --- The number of samples

\sum np = 87 --- Number of leaking tubes

First, we calculate the number of observations

\sum n = n * Samples

\sum n= 135 * 20

\sum n= 2700

Using 3 sigma control limit, we have:

z = 3

Calculate \bar p

\bar p = \frac{\sum np}{\sum n}

So, we have:

\bar p = \frac{87}{2700}

\bar p = 0.0322

Next, calculate the standard deviation

s_p = \sqrt{\frac{\bar p* (1-\bar p)}{n}}

So, we have:

s_p = \sqrt{\frac{0.0322* (1-0.0322)}{135}}

s_p = \sqrt{\frac{0.03116}{135}}

s_p = \sqrt{0.0002308}

s_p = 0.0152

The control limits is then calculated as:

UCL = \bar p + z * s_p --- upper control limit

LCL = \bar p - z * s_p --- lower control limits

So, we have:

UCL = \bar p + z * s_p

UCL = 0.0322 +3 * 0.0152

UCL = 0.078

LCL = \bar p - z * s_p

LCL = 0.0322 - 3 * 0.0152

LCL = -0.013

Since the calculated LCL is less than 0, we simply set it to 0

LCL = 0

So, the p chart control limits are:

UCL = 0.078

LCL = 0

7 0
3 years ago
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