The vector ab has a magnitude of 20 units and is parallel to the
vector 4i + 3j. Hence, The vector AB is 16i + 12j.
<h3>How to find the vector?</h3>
If we have given a vector v of initial point A and terminal point B
v = ai + bj
then the components form as;
AB = xi + yj
Here, xi and yj are the components of the vector.
Given;
The vector ab has a magnitude of 20 units and is parallel to the
vector 4i + 3j.
magnitude

Unit vector in direction of resultant = (4i + 3j) / 5
Vector of magnitude 20 unit in direction of the resultant
= 20 x (4i + 3j) / 5
= 4 x (4i + 3j)
= 16i + 12j
Hence, The vector AB is 16i + 12j.
Learn more about vectors;
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Step-by-step explanation:
In simplify form: 1.3x+2.4-6.1-3.2 = -4.8x-0.8
or factor the expression: =-4/5×(6x+1) Alternate form: -0.8(6x+1). I hope this helps.
Hello,
n=1,2,3,.... and not 0
Answer B a(n)=-2*n
The anser is 20 that what i think
E^x^2 - 9 = 1
e^x^2 = 1 + 9 = 10
Ln e^x^2 = Ln 10
x^2 = Ln 10
x = sqrt (Ln 10) = 1.517
x = 1.517