Answer:
Step-by-step explanation:
In a deck of cart, we have:
a = 4 (aces)
t = 4 (three)
j = 4 (jacks)
And the total number of cards in the deck is
n = 52
So, the probability of drawing an ace as first cart is:
At the second drawing, the ace is not replaced within the deck. So the number of cards left in the deck is
Therefore, the probability of drawing a three at the 2nd draw is
Then, at the third draw, the previous 2 cards are not replaced, so there are now
cards in the deck. So, the probability of drawing a jack is
Therefore, the total probability of drawing an ace, a three and then a jack is:
Answer: 11/20
55/100 simplified is 11/20
We don’t know the value of the shorter side, so we will categorize it as x. Side 2 is just 4 feet longer than x, so we would add 4 on to it. Side 3 has double the x, so we would multiply it be 2 for 2x, and subtract the 4 feet from it.
Side 1: x
Side 2: x + 4
Side 3: 2x - 4
If the perimeter is 64 feet, then all of the sides have to add up to it. Therefore, first we add all of the side lengths up:
x + x + 4 + 2x - 4 = 4x.
Now we put 4x, the amount of all these sides added up, equal to the perimeter of 64.
4x = 64. Divide both sides by 4 to get x by itself.
x = 16.
Now that we know x is 16, we will substitute it in for all the side lengths’ equations.
We know that Side 1 was just x, so that will be 16. Since Side 2 was 4 more than x, we’d do 16 + 4 = 20. We substitute 16 in for x in Side 3’s equation: 2(16) - 4 = 32 - 4 = 28.
Therefore, the final lengths of all the sides are:
Side 1: 16
Side 2: 20
Side 3: 28
