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sp2606 [1]
3 years ago
10

I Need Assistance With This:

Mathematics
1 answer:
Tamiku [17]3 years ago
5 0

Answer:

22.5 in^2

Step-by-step explanation:

h = 3 in

base 1 = 6 in

base 2 = 9 in

So plug in

A = 1/2 (3) (6 + 9)

A = 3/2 (15)

A = 22.5 in^2

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Step-by-step explanation:

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4. Solve the system using substitution.
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3 0
3 years ago
Which expression is equivalent
gtnhenbr [62]

Answer:

Option  B is correct.

\frac{81m^2n^5}{8} is equivalent to \frac{(3m^{-1}n^2)^4}{(2m^{-2}n)^3}

Step-by-step explanation:

Given expression: \frac{(3m^{-1}n^2)^4}{(2m^{-2}n)^3}

Using exponents power:

  • (ab)^n = a^nb^n
  • (a^n)^m = a^{nm}
  • a^m \cdot a^n = a^{m+n}

Given: \frac{(3m^{-1}n^2)^4}{(2m^{-2}n)^3}

Apply exponent power :

⇒ \frac{3^4 (m^{-1})^4(n^2)^4}{2^3(m^{-2})^3 n^3}

⇒ \frac{81 m^{-4}n^8}{8m^{-6}n^3} = \frac{81 m^{-4} \cdot m^6 n^8 \cdot n^{-3}}{8}

⇒\frac{81 m^{-4+6} n^{8-3}}{8} = \frac{81 m^2 n^5}{8} = \frac{81m^2 n^5}{8}

Therefore, the expression which is equivalent to  \frac{(3m^{-1}n^2)^4}{(2m^{-2}n)^3} is,  \frac{81m^2 n^5}{8}

4 0
3 years ago
Read 2 more answers
Can someone please help mee
disa [49]

Answer:

I think that this answer is 22

3 0
2 years ago
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