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zhannawk [14.2K]
3 years ago
12

Need help I don’t understand

Biology
1 answer:
lisabon 2012 [21]3 years ago
5 0

its asking for you to check the box if the item is preset in the cell hint: eukaryotic cells have a nucleus so you would say yes in the box. but since prokaryotic cells don't have a nucleus say no in the box

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The bones from an animal found at an archaeological dig have a C614 activity of 0.10 Bq per gram of carbon. The half-life of C61
erastova [34]

C14 is an isotope used in radiocarbon dating techniques to date organic matter remains. The age of these bones is approximately<u> 6890 years.</u>

<h3>What is Carbon 14?</h3>

Carbon 14, also known as radiocarbon, is a radioactive carbon isotope.

Isotopes are the atoms of the same element -carbon- that vary in neutrons and, hence, in their massic number. They are alternative forms of the same element.

The radioactive C14 nucleus contains 6 protons and 8 neutrons and has a half-life of 5730 years.

The term half-life is a reference. It means that an organism that has been dead for 5730 years has half the C14 amount or concentration than the same organism had when it was alive.

Knowing the half-life of an element is useful to determine the age of the dead matter.

C14 is used in radiocarbon dating techniques or methods to estimate the age of fossils. This is a reliable technique used for dating organic samples that are less than 50,000 years old.

<u>Available data</u>:

  • The half-life of C14 is 5730 years
  • Bones activity of 0.10 Bq per gram of carbon

To answer this question we can make use of the following equation

Ln (C14T₁/C14 T₀) = - λ T₁

Where,

  • C14 T₀ ⇒ Amount of carbon in a living body. We know, by bibliography, that living organism activity is 0.23 Bq per gram of carbon. So, C14 T₀ = 0.23 Bq/g
  • C14T₁ ⇒ Amount of carbon in the dead body. C14T₁ = 0.1 Bq/g
  • λ ⇒ radioactive decay constant = (Ln2)/T₀,₅
  • T₀,₅ ⇒ The half-life of carbon 14 = 5730 years
  • T₀ = Time when the organism was alive
  • T₁ = Age of bones

Let us first calculate the radioactive decay constant.

λ = (Ln2)/T₀,₅

λ = 0.693/5730

<u>λ = 0.0001209</u>

Now, let us calculate the first term in the equation

Ln (C14T₁/C14 T₀) = Ln (0.1/0.23) = Ln 0.4347 =<u> - 0.833</u>

Finally, let us replace the terms, clear the equation, and calculate the value of T₁.

Ln (C14T₁/C14 T₀) = - λ T₁

- 0.833 = - 0.0001209 x T₁

T₁ = - 0.833 / - 0.0001209

T₁ =  6889.99 ≅ <u>6890 years</u>

The bones are approximately<u> 6890 years.</u>

You can learn more about dating organic matter with carbon14 at

brainly.com/question/4149380

#SPJ1

6 0
2 years ago
If a purple plant cross-breeds with a yellow plant and almost all of the resulting "child" plants are yellow, which is the domin
Sergio [31]
Yellow would be more dominant because most of the kids are yellow so it is more dominant
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3 years ago
Read 2 more answers
Help me please,Thanks
BigorU [14]
Okay. About 71% of the Earth's surface is water. And salt water holds about 96.5% of all the Earth's water. The remaining 3% of freshwater is found in Glaciers and ice caps making it difficult to use because it is frozen. Other places freshwater can be found is: Lakes, swamps, rivers and the atmosphere. I hope this helps!
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Please help I need it done asap!
Thepotemich [5.8K]

Answer:

yes

Explanation:

right

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How might an individual's own cells lead to false verdicts of guilt.
Gre4nikov [31]

Answer:

Through a circumstance known as "secondary transfer DNA", or "Touch DNA".

Explanation:

Most times when a crime is committed, DNA samples are obtained from surfaces in the scene where the crime was committed. There is a very huge possibility of picking up the DNA of someone who was never at the scene of the crime and this is a result of a condition known as Touch DNA.

Because we touch several objects which can be moved to different locations and touch people who are also always mobile, our DNA cells can find their ways to a crime scene where we had never physically been to. This can lead to false verdicts of guilt.

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