The packaging one is Golgi apparatus that’s all I know sorry sis
The number of days when the season pass would be less expensive than the daily pass is 5 days.
<h3>How many days would the season pass be less expensive?</h3>
The equation that represents the total cost of skiing with the daily pass : (daily pass x number of days) + (cost of renting skis x number of days)
$70d + $20d = $90d
The equation that represents the total cost of skiing with the seasonal pass : cost of season pass + (cost of renting skis x number of days)
$300 + $20d
When the season pass becomes less expensive, the inequality equation is:
Daily pass > season pass
$90d > $300 + $20d
In order to determine the value of d, take the following steps:
Combine and add similar terms: $90d - $20d > $300
70d > $300
Divide both sides by 70 d > $300 / 70
d > 4.3 days
Approximately 5 days.
To learn more about how to calculate inequality, please check: brainly.com/question/13306871
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Answer:
23,230
Step-by-step explanation:
230 is ten times larger than 23, and if you add them together is it 253
Answer:
10√2
Step-by-step explanation:
A(1, 4), B(3, 6), C(6, 3), D(4, 1)
The distance formula tells you the distance d between two points (x1, y1) and (x2, y2) is given by ...
d = √((x2-x1)² +(y2-y1)²
Then the side lengths are ...
AB = √(2² +2²) = √8 = 2√2
BC = √(3² +(-3)²) = √18 = 3√2
The perimeter is twice the sum of these sides, so is ...
P = 2(2√2 +3√2) = 10√2 . . . the perimeter of the rectangle
