I'll gladly help you, but I can't really read that.
Answer: y=3x-8, y=5x-8, and y=2x-8
Step-by-step explanation:
These equations are all lines in slope-intercept form (y=mx+b where b is the y-intercept). y=3x-8, y=5x-8, and y=2x-8 all have -8 as the b value. Therefore, these equations have the same y-intercept.
Answer:
c brainliest
Step-by-step explanation:
Check the picture below. Recall, is an open-top box, so, the top is not part of the surface area, of the 300 cm². Also, recall, the base is a square, thus, length = width = x.

so.. that'd be the V(x) for such box, now, where is the maximum point at?

now, let's check if it's a maximum point at 10, by doing a first-derivative test on it. Check the second picture below.
so, the volume will then be at