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Andre45 [30]
3 years ago
5

The difference between two numbers is 9 and the product of the numbers is 162. Find the two numbers

Mathematics
1 answer:
fiasKO [112]3 years ago
7 0
Let the no be X and Y

acc to ques....

x-y=9 .........1

xy=162 ..........2

substituting value from 1 in 2 we get;

x=9+y

[9+y][y] = 162

y^2+9y = 162

y^2 + 9y - 162=0

y^2 + 18y - 9y - 162=0

y[y+18] + 9[y+18]=0

[y+9][y+18}

y= -9.................................3


y= -18......................................4



case 1 :

y= -9

x = 9-9=0

case 2:

y= -18

x= 9-18 = -9
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5. The recursive algorithm given below can be used to compute gcd(a, b) where a and b are non-negative integer, not both zero.
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Implementating the given algorithm in python 3, the greatest common divisors of <em>(</em><em>124</em><em> </em><em>and</em><em> </em><em>244</em><em>)</em><em> </em>and <em>(</em><em>4424</em><em> </em><em>and</em><em> </em><em>2111</em><em>)</em><em> </em>are 4 and 1 respectively.

The program implementation is given below and the output of the sample run is attached.

def gcd(a, b):

<em>#initialize</em><em> </em><em>a</em><em> </em><em>function</em><em> </em><em>named</em><em> </em><em>gcd</em><em> </em><em>which</em><em> </em><em>takes</em><em> </em><em>in</em><em> </em><em>two</em><em> </em><em>parameters</em><em> </em>

if a>b:

<em>#checks</em><em> </em><em>if</em><em> </em><em>a</em><em> </em><em>is</em><em> </em><em>greater</em><em> </em><em>than</em><em> </em><em>b</em>

return gcd (b, a)

<em>#if</em><em> </em><em>true</em><em> </em><em>interchange</em><em> </em><em>the</em><em> </em><em>Parameters</em><em> </em><em>and</em><em> </em><em>Recall</em><em> </em><em>the</em><em> </em><em>function</em><em> </em>

elif a == 0:

return b

elif a == 1:

return 1

elif((a%2 == 0)and(b%2==0)):

<em>#even</em><em> </em><em>numbers</em><em> </em><em>leave</em><em> </em><em>no</em><em> </em><em>remainder</em><em> </em><em>when</em><em> </em><em>divided</em><em> </em><em>by</em><em> </em><em>2</em><em>,</em><em> </em><em>checks</em><em> </em><em>if</em><em> </em><em>a</em><em> </em><em>and</em><em> </em><em>b</em><em> </em><em>are</em><em> </em><em>even</em><em> </em>

return 2 * gcd(a/2, b/2)

elif((a%2 !=0) and (b%2==0)):

<em>#checks</em><em> </em><em>if</em><em> </em><em>a</em><em> </em><em>is</em><em> </em><em>odd</em><em> </em><em>and</em><em> </em><em>B</em><em> </em><em>is</em><em> </em><em>even</em><em> </em>

return gcd(a, b/2)

else :

return gcd(a, b-a)

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print(gcd(124, 244))

print()

<em>#leaves</em><em> </em><em>a</em><em> </em><em>space</em><em> </em><em>after</em><em> </em><em>the</em><em> </em><em>first</em><em> </em><em>output</em><em> </em>

print(gcd(4424, 2111))

Learn more :brainly.com/question/25506437

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Answer:

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Step-by-step explanation:

First I'm making all mixed numbers improper fractions.

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On second look, I ddn't need to do that except for the last one, the change in apple.  When increasing things proportionally you basically multiply everything by the same number.  A simple example.

Say a recipe made 10 of something with 1 of ingredient A and 2 of ingredient B.  Well, what if you made the recipe twice?  that would be 20 things from 2 of A and 4 of B.  This is the same as changing the recipe to make double.  It works if you halve things as well, or multiply by any number or fraction.

So the point is, we changed the amount of apples.  We want to know how much we changed it by, then that much is how much the total number of muffins changes.  So if we doubled apples the muffins would double, but I don't think it's that simple.

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And you can (and should) double check

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9/8 = 9/8

Yay!  If you don't gt fraction multiplication let me know.  But the recipie is an increase of 3/2 or 1.5, so there will be 1.5 as many muffins.

12*1.5 = 12(3/2) = 18

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