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Katen [24]
3 years ago
5

95 POINTS! PLEASE HELP See picture for true or false math problems. Solve all please

Mathematics
1 answer:
givi [52]3 years ago
4 0

Answer:

1) True

2) True

3) False

4) True

5) True

Step-by-step explanation:

1) -2《3 - 3

-2《0

-2》-3 - 2

-2》-5

2) 4 > -3 + 3

4 > 0

4 > 1 + 2

4 > 3

3) -2《0 - 6

-2《-6 is false

4) 0 - 3 < 4

-3 < 4

0 + 3 > -1

3 > -1

5) 0 > -6 - 3

0 > -9

0 < 3 + 6

0 < 9

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PLEASE answer asap ps. 99 POINTS
Dimas [21]
Write the number out:
ex) 2 dots on number 3 so write number 3 twice and etc

3,3,4,5,5,5,6,8,8
find the middle number
5 is the middle number so it’s the median

8 0
3 years ago
Read 2 more answers
Mal spends 7 hours in school each day. Her lunch period is 1 hour long, and she spends a
Alex787 [66]

Answer:

z = 5*(1/2)

z = 5/10

---

time switching classes:

w = 7/10

---

y - 6x - z - w = 0

6x = y - z - w

x = (y - z - w)/6

x = (76/10 - 5/10 - 7/10)/6

x = (76 - 5 - 7)/(10*6)

x = (64)/(10*6)

x = (2*2*2*2*2*2)/(2*5*2*3)

x = (2*2*2*2)/(5*3)

x = 16/15

x = 1.0666666666

---

check:

y = 7 + 3/5

y = 7.6

z = 1/2

z = 0.5

w = 7/10

w = 0.7

y - 6x - z - w = 0

6x = y - z - w

x = (y - z - w)/6

x = (7.6 - 0.5 - 0.7)/6

x = 1.0666666666

---

answer:

z = 5*(1/2)

z = 5/10

---

time switching classes:

w = 7/10

---

y - 6x - z - w = 0

6x = y - z - w

x = (y - z - w)/6

x = (76/10 - 5/10 - 7/10)/6

x = (76 - 5 - 7)/(10*6)

x = (64)/(10*6)

x = (2*2*2*2*2*2)/(2*5*2*3)

x = (2*2*2*2)/(5*3)

x = 16/15

x = 1.0666666666

---

check:

y = 7 + 3/5

y = 7.6

z = 1/2

z = 0.5

w = 7/10

w = 0.7

y - 6x - z - w = 0

6x = y - z - w

x = (y - z - w)/6

x = (7.6 - 0.5 - 0.7)/6

x = 1.0666666666

---

answer:

each class is 1.07 hours

Step-by-step explanation:

8 0
2 years ago
Integrate ​G(x,y,z)equalsz over the parabolic cylinder yequalszsquared​, 0less than or equalsxless than or equals2​, 0less than
yKpoI14uk [10]

I gather you're supposed to compute the integral of G(x,y,z)=z over a surface S that is the part of the parabolic cylinder y=z^2 with 0\le x\le2 and 0\le z\le\frac{\sqrt{15}}2.

We can parameterize S by

\vec s(x,z)=x\,\vec\imath+z^2\,\vec\jmath+z\,\vec k

with the given constraints on x and z. Take the normal vector to S to be

\vec s_x\times\vec s_z=-\vec\jmath+2z\,\vec k

so that the surface element is

\mathrm dS=\|\vec s_x\times\vec s_z\|\,\mathrm dx\,\mathrm dz=\sqrt{1+4z^2}\,\mathrm dx\,\mathrm dz

Then in the integral, we have

\displaystyle\iint_Sz\,\mathrm dS=\int_0^2\int_0^{\sqrt{15}/2}z\sqrt{1+4z^2}\,\mathrm dz\,\mathrm dx=\boxed{\frac{21}2}

5 0
3 years ago
When creating a scatterplot, if the points are too close together to see the relationship, how could you adjust your graph?
Radda [10]
The correct answer for this question is this one: "B. increase your scale values"

<span>When creating a scatterplot, if the points are too close together to see the relationship, You adjust your graph by </span><em>increasing your scale values</em>
Hope this helps answer your question and have a nice day ahead.
5 0
3 years ago
Read 2 more answers
What is the slope and y intercept of y=-x+3
sattari [20]
Y intercept when x =0

<span> y=-x+3
 y = -0 +3
 y = 3

</span><span> the slope is -1 </span>
<span>
</span>
8 0
3 years ago
Read 2 more answers
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