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ddd [48]
3 years ago
12

Use the figure to answer the question. A circle with points C, D, H, and E on the circle and point B in the middle of the circle

. Segments BC, HD, DB, and BE are shown. What is the correct way to name the circle? ⨀E ⨀HD \(\bigodot B\) \(\bigodot BDC\
NEED HELP ASAP
Mathematics
1 answer:
Shalnov [3]3 years ago
7 0

Answer:

  Circle B

Step-by-step explanation:

A circle is named by the name of the point at its center.

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How is the graph of the parent function y=x² transformed to produce the graph of y=3(x+1)²?
Anna11 [10]

Answer:

Step-by-step explanation:

Remark

Always the easiest way to study these questions is to get a graph. The one below shows

Red: y = x^2

Blue: y= 3(x + 1)^2

You will notice that (x+1)^2 shifts the graph Left -- the opposite to what you might think.

The 3 is a little harder. It narrows the red mother graph. Which choice says that?

The choice is between b and d. Why. Because the blue graph is to the left of the red one.

You have to learn the meaning of compressed. A better word might be narrows.

Answer

B

7 0
2 years ago
your class sponsors a benefit concert and the tickets at $8 each.Jordan sells 12 tickets,Andy 16,Morgan 17,and Pat 13.Compute th
Irina18 [472]
Alright, so we have tickets for 8 dollars. The number of tickets can represent x, and the money totaled is 8x. x=16+17+13=46, so we can substitute that in to get 8*46 for the total revenue=368 dollars
8 0
3 years ago
What is the zero in the quadratic function f(x)= 9x^2-54x-19?
Alex17521 [72]

Answer:

6.33... and 0.333...

Step-by-step explanation:

The quadratic formula is


x=\frac{-b+\sqrt{b^2-4ac} }{2a}.


It is important because while some quadratics are factorable and can be solved not all are. The formula will solve all quadratic equations and can also give both real and imaginary solutions.  Using the formula will require less work than finding the factors if factorable. We will substitute a=9, b=-54 and c=-19.

x=\frac{-b+/-\sqrt{b^2-4ac} }{2a}\\x=\frac{-(-54)+/-\sqrt{(-54)^2-4(9)(-19)} }{2(9)}\\x=\frac{54+/-\sqrt{2916+684} }{18}

We will now solve for the plus and the minus.

The plus,,,

x=\frac{54+\sqrt{3600}}{18}\\x=\frac{54+60}{18}\\x=\frac{114}{18}\\x=6.3

and the minus...

x=\frac{54-\sqrt{3600}}{18}\\x=\frac{54-60}{18}\\x=\frac{-6}{18}\\x=-0.333...

8 0
4 years ago
Need help please help me
Ostrovityanka [42]
The solution is the point of intersection between the two equations.

Assuming you have a graphing calculator or a program to lets you graph equations (I use desmos) you simply put in the equetions and note down the coordinates of the point of intersection.

In the graph the first equation is in blue and the second in red.

The point of intersection = the solution = (-6 , -1)



If you dont have access to a graphing calculator you could draw the graphs by hand;

1) Draw a table of values for each equation; you do this by setting three or four values for x and calculating its image in y (you can use any values of x)

y = 0.5 x + 2 (Im writing 0.5 instead of 1/2 because I find its easier in this format)

x | y
-1 | 1.5 * y = 0.5 (-1) + 2 = 1.5
0 | 2 * y = 0.5 (0) + 2 = 2
1 | 2.5 * y = 0.5 (1) + 2 = 2.5
2 | 3 * y = 0.5 (2) + 2 = 3

y = x + 5

x | y
-1 | 4 * y = (-1) + 5 = 4
0 | 5 * y = (0) + 5 = 5
1 | 6 * y = (1) + 5 = 6
2 | 7 * y = (2) + 5 = 7

2) Plot these point on the graph
I suggest to use diffrent colored points or diffrent kinds of point markers (an x or a dot) to avoid confusion about which point belongs to which graph

3) Using a ruler draw a line connection all the dots of one graph and do the same for the other

4) The point of intersection is the solution

8 0
4 years ago
Read 2 more answers
What is 2^5 in standard notation
elena-14-01-66 [18.8K]
2x2x2x2x2 is 2^5 in standard notation
8 0
3 years ago
Read 2 more answers
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