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defon
2 years ago
12

Please I need help on this problem

Mathematics
2 answers:
elena-s [515]2 years ago
5 0

Answer:

9

Step-by-step explanation:

Iteru [2.4K]2 years ago
3 0

Answer:

81

Step-by-step explanation:

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What is the slope of y = 4 - 2x
NISA [10]

compare with y=mx+c

then

y=4-2x

y=-2x+4

c=4,m=-2

8 0
2 years ago
Read 2 more answers
Suppose that y varies inversely with x. Write a function that models the inverse function. X= 15 when y= 2
yulyashka [42]
The answer to this question is B: <span>y = 30/x. I hoped I have helped you today!</span>
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3 years ago
Given: cos θ=-4/5, sin x = -12/13, θ is in the third quadrant, 
USPshnik [31]

By definition of tangent,

tan(2<em>θ</em>) = sin(2<em>θ</em>) / cos(2<em>θ</em>)

Recall the double angle identities:

sin(2<em>θ</em>) = 2 sin(<em>θ</em>) cos(<em>θ</em>)

cos(2<em>θ</em>) = cos²(<em>θ</em>) - sin²(<em>θ</em>) = 2 cos²(<em>θ</em>) - 1

where the latter equality follows from the Pythagorean identity, cos²(<em>θ</em>) + sin²(<em>θ</em>) = 1. From this identity we can solve for the unknown value of sin(<em>θ</em>):

sin(<em>θ</em>) = ± √(1 - cos²(<em>θ</em>))

and the sign of sin(<em>θ</em>) is determined by the quadrant in which the angle terminates.

<em />

We're given that <em>θ</em> belongs to the third quadrant, for which both sin(<em>θ</em>) and cos(<em>θ</em>) are negative. So if cos(<em>θ</em>) = -4/5, we get

sin(<em>θ</em>) = - √(1 - (-4/5)²) = -3/5

Then

tan(2<em>θ</em>) = sin(2<em>θ</em>) / cos(2<em>θ</em>)

tan(2<em>θ</em>) = (2 sin(<em>θ</em>) cos(<em>θ</em>)) / (2 cos²(<em>θ</em>) - 1)

tan(2<em>θ</em>) = (2 (-3/5) (-4/5)) / (2 (-4/5)² - 1)

tan(2<em>θ</em>) = 24/7

4 0
3 years ago
What is the side length of a cube that has a volume of 0.008 m
Nataliya [291]
Let the side lenght of cube is a
voluem of cube= 0.008
a^3=0.008
a =0.2
side of lenght is 0.2
8 0
3 years ago
Slope m<br> = 2<br> y-intercept b = ?<br> =<br> Equation ?
Norma-Jean [14]
Answer:

Slope m = 2

y-intercept b = 100

Equation: y = 2x + 100
8 0
2 years ago
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