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DIA [1.3K]
3 years ago
12

LAST QUESTION!!!!!!!!!!!

Mathematics
1 answer:
bogdanovich [222]3 years ago
4 0

Answer:

Just put the opposite coordinates on the other side of the segment and thats your answer!

Step-by-step explanation:

You might be interested in
Find the sum or difference
uysha [10]
You just add up all the numbers in each position
so
-10 -1 5
-4 14 1
so C
5 0
3 years ago
Oxford currently generates 45,000 tons of garbage per year. but the city is launching some recycling initiatives to bring that n
barxatty [35]

Answer:

-Exponential Decay

-Decay factor is (1-0.05)

Step-by-step explanation:

-Given that the number decreases by a defined rate each year from the initial size by 5%,

-This is an exponential decay function of the form:

y=Ae^{-rt}

Where:

y is the quantity/size after time t

A is the initial size

r is the rate of decay

-Our function can the be written as

y=45000e^{-0.05t}

Hence, the decay rate/factor is 0.05

#Alternatively

The exponential decay can be of the form:

y=ab^x

Where:

y is the size at time x, a is the initial size, x is time and b is the decay factor.

b is of the form b=(1-r),\ \  r=decay\  rate

y=ab^x\\\\y=45000(1-0.05)^x

Hence, the decay factor is (1-0.05)

8 0
3 years ago
Bridget bought a package of cookies for $1.50 and 5 water. She spent a total of $10. How much did each water cost?
andrew-mc [135]

Answer:

I think it would be, $8.50 OR $9.50

Step-by-step explanation:

You just have to take $1.50 from $10.00 :)

6 0
3 years ago
Determine the value of k for which -3x^2+12x+k=0 has no real roots. ​
Crazy boy [7]

Answer:

K<-12

Step-by-step explanation:

+ For that, we need the delta negatif.

+ The delta= b^2-4ac=12^2-4(-3)(k)=144+12k<0

Then, 12k<-144 (divise both sides by 12)

we have k<-12

Or an other way:

-3x^2+12x+k=0  (divise both sides by -3)

x^2-4x-k/3=0

x^2-4x+4 -4-k/3=0

(x-2)^2=4+k/3

Now , we need 4+k/3<0, k/3<-4 or k<-12

Hope you understand.

4 0
3 years ago
I need help asap.
DaniilM [7]
1+10 < or equal to 40
5 0
3 years ago
Read 2 more answers
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