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beks73 [17]
3 years ago
13

If you had an hour a week to spend with a low-achieving 3rd grader, over say, six weeks, what would you focus on with them?

Mathematics
2 answers:
pav-90 [236]3 years ago
4 0
I'm not sure if this is exactly an opinionated question but I'm going to answer in my own personal opinion. In third grade I really struggled with memorizing Division and multiplication so honestly I would work on that and memorizing the multiplication table and just I guess how to do division and I would also teach that third-grader all of the life hacks for remembering answers to multiplication questions. For example I would teach them the products of 9 lifehack.
eduard3 years ago
3 0
It's a good question. I've gone through it many times.

You can't do much with an hour in a week for six weeks, even with a 3rd grader. That's the bad news. The good news is that if you get him or her to work with you, and give them a second hour, you might be able to do something. What I would focus on depends on what I find out about what they can do. It also depends on how they take in information. Most people (almost all) learn either by hearing or seeing. Most younger children learn better by doing than by being told.

Always try and make some of what you do physical. You didn't mention the subject area, but I'm assuming mathematics because that's where you listed it.

Find out what your jurisdiction expects a third grader to do. Talk to the teacher if you are the parent of such a child. The process of learning is an extremely complex task. Don't take it on if you are flying blind and are unable to talk to the teacher. You need to be the parent or you need to take the parent along. In almost every place, no teacher will talk to someone who is unrelated to the child.

When you know more about the child, post again. I don't know exactly how you can contact me again (perhaps making me a friend), but when you know more, you are perfectly welcome to contact me again.
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The monthly cost of driving a car depends on the number of miles driven. Lynn found that in May her driving cost was $380 for 48
dlinn [17]

Answer:

a) see attachment

b) Cost f(distance) = 0.25d + 260

c) $0.25

Step-by-step explanation:

b) The linear relationship between two variables is as follows:

C f(d) = m*d + k .... Eq 1

Where, m and k are constants to be evaluated

Find m: we will find slope of the line between two points (480,$380) & (800,$460)

Slope of line (m) = \frac{460-380}{800-480} = $0.25 / mile

Find k: consider one of the two points and input in Eq 1 using (480,$380)

k = 380 - 0.25(480) = $260

The equation of line is C f(d) = 0.25*d +260.

We can use this equation for plotting the graph for part a

c) Rate of cost / mile is given by the slope of the graph if scruutinized on the units; hence, $0.25

5 0
3 years ago
Given the midpoint of (-10,7) and the endpoint of (5,-3), what is the other endpoint?
xxMikexx [17]

(-25,17)


Hope this helps.

4 0
3 years ago
Factor completely x3 + 8x2 − 3x − 24.
balu736 [363]

Answer:

x=8=2=3

Step-by-step explanation:

6 0
3 years ago
I = $16 P = $200 T = 2 years
Nezavi [6.7K]
Next time, please include the instructions with your post.

The formula for simple interest is    i = p*r*t, where r is the annual interest rate expressed as a decimal fraction.

Here, $16 = $200*r*2, with r being the unknown.

Solving for r:    r = $16  /  $400   =  0.04  (answer)
4 0
3 years ago
In two or more complete sentences, describe how to find the interval(s) where the function is increasing and how interval notati
Novay_Z [31]

Answer:

(-5,0)

Step-by-step explanation:

In case when you tracking the finger across the line, at which there is an increase or decrease in y axis so this is we called intervals. Moreover, the interval notation is also necessary as it depicts the beginning and ending points. In this, the first number denotes the minimum number while the second number denotes the maximum number

For Decreasing:

(-8,-5)

(4,8)

For Increasing:

(-5,0)

5 0
4 years ago
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