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Natasha_Volkova [10]
3 years ago
14

I’m not sure how to get the gradient

Mathematics
1 answer:
snow_tiger [21]3 years ago
5 0
The gradient is 2.

You divide the increase in y (2) by the increase in x (1)
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Show that x2 +x-3=0 has a solution between 1 and 2
Natali5045456 [20]

Answer:

here is the answer

Step-by-step explanation:

hope it is helpful

7 0
3 years ago
The length of a rectangle is increasing at a rate of 9 cm/s and its width is increasing at a rate of 4 cm/s. When the length is
Setler [38]

Answer:

The area of the rectangle is increasing at a rate of 168 square centimeters per second.

Step-by-step explanation:

Geometrically speaking, the area of a rectangle (A), in square centimeters, is described by following expression:

A = w\cdot l (1)

Where:

w - Width, in centimeters.

h - Height, in centimeters.

By Differential Calculus, we find an expression for the rate of change of the area of the rectangle (\dot A), in square centimeters per second:

\dot A = \dot w\cdot l + w\cdot \dot l (2)

Where:

\dot w - Rate of change of the width of the rectangle, in centimeters per second.

\dot l - Rate of change of the length of the rectangle, in centimeters per second.

If we know that w = 12\,cm, l = 15\,cm, \dot w = 4\,\frac{cm}{s} and \dot l = 9\,\frac{cm}{s}, then the rate of change of the area of the rectangle is:

\dot A = \dot w\cdot l + w\cdot \dot l

\dot A = 168\,\frac{cm^{2}}{s}

The area of the rectangle is increasing at a rate of 168 square centimeters per second.

6 0
3 years ago
Simplify each polynomial. 6g+8k-9g+2k<br> -4x+6x²+5x<br> a²+5a-3a²<br> 3x²+8x+7x
notsponge [240]
1. 10k-3g
2. 6x squared +x
3. 5a-2a squared
4.3x squared+15x
6 0
3 years ago
REALLY NEED HELP<br><br> Evaluate the following expression.<br><br> (−2.2 )·(−2)·(−14)·(5)
Lisa [10]

Answer:

-308

Step-by-step explanation:

Given that:

=(−2.2 )·(−2)·(−14)·(5)

  • As "-" sign into "-" becomes "+"
  • (2.2)(2) = 4.4

=(4.4)*(-14).(5)

  • As (-14)*(5)  = -70

=(4.4)*(-70)

  • Multiplying 4.4 with -70

= -308

I hope it will help you.

8 0
3 years ago
Help Me! I suck with vectors.<br> Look at the attached pictures for the problem.
Westkost [7]

Multiplying a vector x by a constant k gives you a new vector whose components are the same as x, but scaled by k:

x=\langle x_1,x_2\rangle\implies x=\langle kx_1,kx_2\rangle

So we have

u=\langle5,-7\rangle\implies-6u=\langle-30,42\rangle

v=\langle-11,3\rangle\implies2v=\langle-22,6\rangle

Vector addition is just a matter of adding the corresponding components together:

x=\langle x_1,x_2\rangle,y=\langle y_1,y_2\rangle\implies x+y=\langle x_1+y_1,x_2+y_2\rangle

Then

2v-6u=\langle-22,6\rangle+\langle-30,42\rangle=\langle-22-30,6+42\rangle

\implies\boxed{2v-6u=\langle-52,48\rangle}

\|x\| denotes the norm/magnitude of the vector x:

x=\langle x_1,x_2\rangle\implies\|x\|=\sqrt{{x_1}^2+{x_2}^2}

We have

\|2v-6u\|=\sqrt{(-52)^2+48^2}=4\sqrt{313}

\implies\boxed{\|2v-6u\|\approx70.77}

7 0
4 years ago
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