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Setler [38]
2 years ago
13

Binomials: Expand (2a+3)^3 (PLEASE ANSWER QUICKLY)

Mathematics
1 answer:
hodyreva [135]2 years ago
4 0

Answer:

8 {a}^{3}  +  {36a}^{2} +  54a + 27 \\

Explanation:

Binomial theorem,

{(p + q)}^{3}  =  {p}^{3}  + 3 {p}^{2} q +  {q}^{3}

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Citrus2011 [14]
The answer is 500 seconds it’s 5.33 minutes.
7 0
3 years ago
Cassidy's diving platform is 6 ft above the water. One of her dives can
avanturin [10]

Answer:

Before coming back up to the surface the maximum depth, Cassidy went was 6.25 ft. below the water surface

Step-by-step explanation:

The height of Cassidy's diving platform above the water = 6 ft.

The equation that models her dive is d = x² - 7·x + 6

Where;

d = Her vertical position or distance from the water surface

x = Here horizontal distance from the platform

At Cassidy's maximum depth, we have;

dd/dx = d(x² - 7·x + 6)/dx = 2·x - 7 = 0

x = 7/2 = 3.5

∴ At Cassidy's maximum depth, x = 3.5 ft.

The maximum depth, d_{max} = d(3.5) = 3.5² - 7 × 3.5 + 6 = -6.25

The maximum depth, Cassidy went before coming back up to the surface = d_{max} = -6.25 ft = 6.25 ft. below the surface of the water.

8 0
3 years ago
Fill in the boxes please
IRINA_888 [86]

Answer:

x=12, DO=45O, G=45, DG=90

Step-by-step explanation:

Mid point means both lenghts are equal

4x-3=2x+21

2x=24

X=12

-----------------

1)4(12)-3=48-3=45

2)2(12)+21=24+21=45

-----------------------------

DO=45

OG=45

DG=90

4 0
3 years ago
Read 2 more answers
Unit 8 right triangles and trigonometry homework 3 similar right triangles and geometric mean
Ugo [173]

The right triangles that have an altitude which forms two right triangles

are similar to the two right triangles formed.

Responses:

1. ΔLJK ~ ΔKJM

ΔLJK ~ ΔLKM

ΔKJM ~ ΔLKM

2. ΔYWZ ~ ΔZWX

ΔYWZ ~ ΔYZW

ΔZWX ~ ΔYZW

3. x = <u>4.8</u>

4. x ≈ <u>14.48</u>

5. x ≈ <u>11.37</u>

6. G.M. = <u>12·√3</u>

7. G.M. = <u>6·√5</u>

<u />

<h3>What condition guarantees the similarity of the right triangles?</h3>

1. ∠LMK = 90° given

∠JMK + ∠LMK  = 180° linear pair angles

∠JMK = 180° - 90° = 90°

∠JKL ≅ ∠JMK All 90° angles are congruent

∠LJK ≅ ∠LJK reflexive property

  • <u>ΔLJK is similar to ΔKJM</u> by Angle–Angle, AA, similarity postulate

∠JLK ≅ ∠JLK by reflexive property

  • <u>ΔLJK is similar to ΔLKM</u> by AA similarity

By the property of equality for triangles that have equal interior angles, we have;

  • <u>ΔKJM ~ ΔLKM</u>

2. ∠YWZ ≅ ∠YWZ by reflexive property

∠WXZ ≅ ∠YZW all 90° angle are congruent

  • <u>ΔYWZ is similar to ΔZWX</u>, by AA similarity postulate

∠XYZ ≅ ∠WYZ by reflexive property

∠YXZ ≅ ∠YZW all 90° are congruent

  • <u>ΔYWZ is similar to ΔYZW</u> by AA similarity postulate

Therefore;

  • <u>ΔZWX ~ ΔYZW</u>

3. The ratio of corresponding sides in similar triangles are equal

From the similar triangles, we have;

\dfrac{8}{10} = \mathbf{ \dfrac{x}{6}}

8 × 6 = 10 × x

48 = 10·x

  • x = \dfrac{48}{10} = \underline{4.8}

3. From the similar triangles, we have;

\mathbf{\dfrac{20}{29}} = \dfrac{x}{21}

20 × 21 = x × 29

420 = 29·x

  • x = \dfrac{420}{29 } \approx \underline{14.48}

4. From the similar triangles, we have;

\mathbf{\dfrac{20}{52}} = \dfrac{x}{48}

20 × 48 = 52 × x

  • x = \dfrac{20 \times 48}{52}  = \dfrac{240}{13}  \approx \underline{18.46}

5. From the similar triangles, we have;

\mathbf{\dfrac{13.2}{26}} = \dfrac{x}{22.4}

13.2 × 22.4 = 26 × x

  • x = \dfrac{13.2 \times 22.4}{26} \approx \underline{ 11.37}

6. The geometric mean, G.M. is given by the formula;

G.M. = \mathbf{\sqrt[n]{x_1 \times x_2 \times x_3  ... x_n}}

The geometric mean of 16 and 27 is therefore;

  • G.M. = \sqrt[2]{16 \times 27}  = \sqrt[2]{432} = \sqrt[2]{144 \times 3} = \mathbf{12 \cdot \sqrt{3}}

  • The geometric mean of 16 and 27 is <u>12·√3</u>

<u />

7. The geometric mean of 5 and 36 is found as follows;

G.M. = \sqrt[2]{5 \times 36}  = \sqrt[2]{180} = \sqrt[2]{36 \times 5} = \mathbf{ 6 \cdot \sqrt{5}}

  • The geometric mean of 5 and 36 is <u>6·√5</u>

Learn more about the AA similarity postulate and geometric mean here:

brainly.com/question/12002948

brainly.com/question/12457640

7 0
3 years ago
Mariah is debating whether to use a straightedge and compass or a computer drawing program to complete a construction of a regul
marshall27 [118]
I think the best way is to use a computer drawing program in constructing a regular hexagon inscribed in a circle. Its because a computer program is an accurate, precise and the most important it is more efficient than using the straight edge and compass
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