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2 years ago

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I don’t get this someone pls help me out??

1 answer:

Natalka [10]2 years ago

8 0

Hisuewbw bshs Snajesb shahs s s

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What is the factor of this problem?<br> ~plz help I cannot get this wrong !

lapo4ka [179]

Answer:

the awencer is 4.2

Step-by-step explanation:

7 0

2 years ago

Trigonometry lesson. Find X and Y

noname [10]

Answer:

12 =x

20.78460969=y

Step-by-step explanation:

sin theta = opposite side / hypotenuse

sin 60 = y /24

Multiply each side by 24

24 sin 60 = y/24*24

24 sin 60 =y

20.78460969=y

cos theta = adjacent side / hypotenuse

cos 60 = x /24

Multiply each side by 24

24*cos 60 = x/24*24

24 cos 60=x

12 =x

7 0

2 years ago

1. Fill in the blank:

liberstina [14]

Step-by-step explanation:

Pi (Ratio of the Circumference of a Circle to Its Diameter) Circles are all similar, and "the circumference divided by the diameter" produces the same value regardless of their radius. This value is the ratio of the circumference of a circle to its diameter and is called π (Pi).

8 0

1 year ago

Find a cubic function with the given zeros.

Fed [463]

Answer:

The correct option is D) $f(x) = x^3 + 2x^2 - 2x - 4$ .

Step-by-step explanation:

Consider the provided cubic function.

We need to find the equation having zeros: Square root of two, negative Square root of two, and -2.

A "zero" of a given function is an input value that produces an output of 0.

Substitute the value of zeros in the provided options to check.

Substitute x=-2 in $f(x) = x^3 + 2x^2 - 2x + 4$ .

$f(x) = x^3 + 2x^2 - 2x + 4\\f(x) = (-2)^3 + 2(-2)^2 - 2(-2) + 4\\f(x) =-8 + 2(4)+4 + 4\\f(x) =8$

Therefore, the option is incorrect.

Substitute x=-2 in $f(x) = x^3 + 2x^2 + 2x - 4$ .

$f(x) = x^3 + 2x^2 + 2x - 4\\f(x) = (-2)^3 + 2(-2)^2 + 2(-2) - 4\\f(x) =-8+2(4)-4-4\\f(x) =-8$

Therefore, the option is incorrect.

Substitute x=-2 in $f(x) = x^3 - 2x^2 - 2x - 4$ .

$f(x) = x^3 - 2x^2 - 2x - 4\\f(x) = (-2)^3 - 2(-2)^2 - 2(-2) - 4\\f(x) =-8-8+4-4\\f(x) =-16$

Therefore, the option is incorrect.

Substitute x=-2 in $f(x) = x^3 + 2x^2 - 2x - 4$ .

$f(x) = x^3 + 2x^2 - 2x - 4\\f(x) = (-2)^3+2(-2)^2 - 2(-2) - 4\\f(x) =-8+8+4-4\\f(x) =0$

Now check for other roots as well.

Substitute x=√2 in $f(x) = x^3 + 2x^2 - 2x - 4$ .

$f(x) = x^3 + 2x^2 - 2x - 4\\f(x) = (\sqrt{2})^3+2(\sqrt{2})^2 - 2(\sqrt{2}) - 4\\f(x) =2\sqrt{2}+4-2\sqrt{2}-4\\f(x) =0$

Substitute x=-√2 in $f(x) = x^3 + 2x^2 - 2x - 4$ .

$f(x) = x^3 + 2x^2 - 2x - 4\\f(x) = (-\sqrt{2})^3+2(-\sqrt{2})^2 - 2(-\sqrt{2}) - 4\\f(x) =-2\sqrt{2}+4+2\sqrt{2}-4\\f(x) =0$

Therefore, the option is correct.

8 0

2 years ago

(s+12)+(-3s-8) equals?

finlep [7]

Answer:

-2s + 4

General Formulas and Concepts:

Combining like terms

Step-by-step explanation:

<u>Step 1: Define expression</u>

(s + 12) + (-3s - 8)

<u>Step 2: Simplify</u>

Combine like terms (s): -2s + 12 - 8
Combine like terms (constants): -2s + 4

4 0

2 years ago