The area of a regular hexagon is
... A = (3√3)/2×s² . . . . . where s is the side length
Of course, the 6-sided figure will have a side length that is 1/6 of the perimeter.
... s = (48 in)/6 = 8 in
... A = (3√3)/2×(8 in)² = 96√3 in² . . . area of your regular hexagon
Answer:
x = 13
Step-by-step explanation:
Here, we want to get the missing side
from what we have, the triangle is a right angled triangle
In this kind of triangle, the Pythagoras’ theorem works
The square of the side facing the right angle ( marked x here) is equal to the sum of the squares of the two other sides
We have this as;
x^2 = 5^2 + 12^2
x^2 = 25 + 144
x^2 = 169
x = √169
x = 13
Answer:
c
Step-by-step explanation:
2x - 3 < 11 or 8x -10 < 82: <span>X < 23/2
<span>
Part 1</span>
</span>2x-3<11
Add 3 both sides
2x-3+3<11+3
Refine
2x<14
Divide by 2 on both sides
2x / 2 / 14 / 2
Refine
x < 7
<span>
Part 2</span>
8x-10<82
Add 10 to both sides
8x-10+10<82+10
Refine
8x<92
Divide by 8
8x / 8 / 92 / 8
Refine
x < 23 / 2
