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Tanya [424]
3 years ago
11

Which expression could be used to find the volume of the prism below?

Mathematics
1 answer:
Minchanka [31]3 years ago
7 0

Answer:

I think its either C or D but im not very sure.

Step-by-step explanation:

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25 POINTS PLEASE HELP ME!! Sam conjectures that for x ≤ - 2, it is true that x^5 + 7 > x^3. Is Sam’s conjecture correct? Why
CaHeK987 [17]

The true statement about Sam’s conjecture is that the conjecture is not correct

<h3>How to determine if Sam’s conjecture is correct or not?</h3>

Sam’s conjecture is given as:

For x ≤ - 2

It is true that x^5 + 7 > x^3.

The inequality x ≤ - 2 means that the highest value of x is -2

Assume the value of x is -2, then we have:

(-2)^5 + 7 > (-2)^3

Evaluate the exponents

-32 + 7 > -8

Evaluate the sum

-25 > -8

The above inequality is false because -8 is greater than -25 i.e. -8 > -25 or -25 < -8

Hence, the true statement about Sam’s conjecture is that the conjecture is not correct

Read more about conjectures at

brainly.com/question/20409479

#SPJ1

5 0
1 year ago
Which of the following is the decimal 0.6250 written as a fraction in lowest form
geniusboy [140]
The answer is 5/8. Hope this helps
6 0
3 years ago
Can someone help me with this graph please
Veronika [31]
These are the answers to your questions

a.In short supply
b.5
c.5
8 0
1 year ago
If function f is a cubic polynomial which statement most accurately describes the function over the interview (0,1)
inysia [295]

Answer:

Option (B)

Step-by-step explanation:

From the given table,

With the increase in the values of x (from x = -2 to x = 2), values of the function is decreasing from x =2 to x = 4.

Interval (0, 1) lies in the domain of the function in which the y-values of the function are,

At x = 0,

f(0) = -6

At x = 1,

f(1) = 0

Therefore, values of the given function are increasing in the interval of (0, 1).

Option (B) will be the correct option.

7 0
3 years ago
PLS HELP I NEED IT LIKE RIGHT NOW
horrorfan [7]

Answer: I am pertty sure it is the letter "D".

3 0
3 years ago
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