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Alexxandr [17]
3 years ago
15

Methane is gas that is found in small quantities in Earth's atmosphere. Methane is the simplest hydrocarbon, consisting of one c

arbon atom and four hydrogen atoms. It is a powerful greenhouse gas, flammable, and used as a fuel worldwide. Construct an explanation of how carbon and hydrogen combine to form methane. A) Nonmetal carbon shares valence electrons with each nonmetal hydrogen forming four covalent bonds. B) Carbon and hydrogen are nonmetals and they share their valence electrons to become ions and form ionic bonds C) Nonmetal carbon loses a valence electron and the nonmetal, hydrogen gains a valence electron to form an ionic bond. D) Hydrogen loses a valence electron to become a cation and carbon gains a valence electron to become an anion forming a covalent bond.
Chemistry
1 answer:
tangare [24]3 years ago
8 0

Answer:

A) Nonmetal carbon shares valence electrons with each nonmetal hydrogen forming four covalent bonds.

Explanation:

Methane is formed when nonmetal carbon shares valence electrons with each nonmetal hydrogen forming four covalent bonds. Nonmetals share electrons to form covalent bonds.

Good luck! :)

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Complete combustion of 7.40 g of a hydrocarbon produced 22.4 g of CO2 and 11.5 g of H2O. What is the empirical formula for the h
cluponka [151]
<span>C2H5 First, you need to figure out the relative ratios of moles of carbon and hydrogen. You do this by first looking up the atomic weight of carbon, hydrogen, and oxygen. Then you use those atomic weights to calculate the molar masses of H2O and CO2. Carbon = 12.0107 Hydrogen = 1.00794 Oxygen = 15.999 Molar mass of H2O = 2 * 1.00794 + 15.999 = 18.01488 Molar mass of CO2 = 12.0107 + 2 * 15.999 = 44.0087 Now using the calculated molar masses, determine how many moles of each product was generated. You do this by dividing the given mass by the molar mass. moles H2O = 11.5 g / 18.01488 g/mole = 0.638361 moles moles CO2 = 22.4 g / 44.0087 g/mole = 0.50899 moles The number of moles of carbon is the same as the number of moles of CO2 since there's just 1 carbon atom per CO2 molecule. Since there's 2 hydrogen atoms per molecule of H2O, you need to multiply the number of moles of H2O by 2 to get the number of moles of hydrogen. moles C = 0.50899 moles H = 0.638361 * 2 = 1.276722 We can double check our math by multiplying the calculated number of moles of carbon and hydrogen by their respective atomic weights and see if we get the original mass of the hydrocarbon. total mass = 0.50899 * 12.0107 + 1.276722 * 1.00794 = 7.400185 7.400185 is more than close enough to 7.40 given rounding errors, so the double check worked. Now to find the empirical formula we need to find a ratio of small integers that comes close to the ratio of moles of carbon and hydrogen. 0.50899 / 1.276722 = 0.398669 0.398669 is extremely close to 4/10, so let's reduce that ratio by dividing both top and bottom by 2 giving 2/5. Since the number of moles of carbon was on top, that ratio implies that the empirical formula for this unknown hydrocarbon is C2H5</span>
3 0
3 years ago
How many miles are in 215 grams of water
Irina18 [472]
You're off to a good start, now find the mass of H2O and put it under I mol,

then multiply 1 mol over the mass of H2O by 215 grams
3 0
3 years ago
Select the correct answer. Which statement best describes how chemical equations demonstrate conservation of mass? OA The number
timofeeve [1]

Answer: C. The number of atoms of each element is the same on each side of the equation.

Explanation:

The Law of Conservation of Matter shows that it is not possible for matter to either be created nor for it to be destroyed so the number of atoms of each element on the reactant side of the equation must equal the number of atoms in each element on the product side of the equation.

This is why the following equation is incomplete:

H₂ + O₂ ⇒ H₂O

The oxygen atoms are not the same on either side.

Equation will therefor have to be balanced which will make it:

2H₂ + O₂ ⇒ 2H₂O

Notice now that atoms are the same on both sides.

8 0
3 years ago
How to prepare 1m of a solution​
jenyasd209 [6]

Answer:

To prepare a 1 M solution, slowly add 1 formula weight of compound to a clean 1-L volumetric flask half filled with distilled or deionized water. Allow the compound to dissolve completely, swirling the flask gently if necessary.

Explanation:

have a great day ahead ♥️

5 0
3 years ago
5. Uranium has three common isotopes. If the abundance of 2U which has an atomic mass of 233.878 amu is 0.01%, the
Temka [501]

Uranium has three common isotopes. The average atomic mass of uranium is 23.7 u/atom.

<h3>What are isotopes?</h3>

Isotopes are similar elements that have a different number of protons.

Uranium has three isotopes

The abundance of 2U has an atomic mass of 233.878 is 0.01%

The abundance of U has a mass of 234.892 amu is 0.71%

The **U has an atomic mass of 237.911 amu is 99.28%

Let's assume we have 10 000 atoms of Uranium

Mass of the 0.01 atoms = 0.01 x 233.878 = 2.33878

Mass of the 0.71 atoms =  0.71 x 234.892 = 166.773

Mass of the 99.28 atoms = 99.28 x 237.911 = 23,619.80

2.33878 + 166.773 + 23,619.80 = 23,788.8

23,788.8 / 1000 = 23.7 u/atom

Thus, the average atomic mass of uranium is 23.7 u/atom.

To learn more about average atomic mass, refer to the link:

brainly.com/question/12971445

#SPJ1

4 0
1 year ago
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