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cluponka [151]
3 years ago
14

Help! I don't know if it's abrasion or ice wedging

Chemistry
2 answers:
alexgriva [62]3 years ago
8 0
It should be “A”. Abrasion
Radda [10]3 years ago
5 0
I think it would be ice wedging
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Describe how the organelles in a cell work together to keep an organism alive​
vodomira [7]

Answer:

These organelles are like the organs in a human and they help the cell stay alive. Each organelle has it's own specific function to help the cell survive. The nucleus of a eukaryotic cell directs the cell's activities and stores DNA. ... All of the cell's organelles must work together to keep the cell healthy.

Explanation:

These organelles are like the organs in a human and they help the cell stay alive. Each organelle has it's own specific function to help the cell survive. The nucleus of a eukaryotic cell directs the cell's activities and stores DNA. ... All of the cell's organelles must work together to keep the cell healthy.

4 0
4 years ago
40 cm3 of acid were mixed with 60 cm3 of alkali in an insulated container. What name is given to this type of reaction?
Stells [14]

Answer:

neutralization reaction

6 0
2 years ago
Atrazine is an herbicide widely used for corn and is a common groundwater pollutant in the corn-producing regions of the United
riadik2000 [5.3K]

Answer:

0.94

Explanation:

Let's assume that the total sample of the soil is 1 cm³; which has a porosity of 0.4 cm³; then the original sample of the soil will be 0.6 cm³

The mass  of the soil particles in 1 cm³ of soil + water = 0.75 g

The fraction of the total atrazine can be calculated by the expression;

Total atrazine =C_w(\frac{g}{mL})*V_w(mL)+C_{(soil)}(\frac{g}{soil})*M_{(soil)}(gsoil)

Also; C_{(soil)}(\frac{g}{soil})= K_{oc}(\frac{mL}{gOC})*f_{oc} (\frac{gOC}{gsoil})*C_w(\frac{g}{mL})

NOTE THAT: K_{oc}( \frac{mL}{gOC})=K_{oc}\frac{L}{kgOC}

Total atrazine can now be calculated as:

C_w*0.4+K_{oc}f_{oc}C_w*0.75 = \frac{C_{soil}*M_{soil}}{Total atrazine}

=\frac{K_{oc}f_{oc}C_w*M_{soil}}{C_w*0.4+K_{oc}f_{oc}C_w*0.75} = \frac{0.75*K_{oc}f_{oc}}{0.4+K_{oc}f_{oc}*0.75}

= \frac{10^{2.52}*0.025*0.75}{0.4+10^{2.52}*0.025*0.75}

= 0.94

Thus,the fraction of total atrazine that will be adsorbed to the soil = 0.94.

3 0
4 years ago
Why would a person could jump further on moon than on Jupiter?
Tomtit [17]
In short, because the moon is smaller, its gravitational force is too. Therefore, if there is less gravity, it would be easier to jump further than on a bigger planet like Jupiter.

Explanation:
The Moon has less mass than the world, which implies it's less gravity than the world further.

Since the gravity is not propulsion on the U.S. as powerfully on the moon because it is on Earth, we are able to jump higher and with a lot of<span> ease.
</span>That's as a result of<span> our muscles (and all </span>alternative<span> body </span>elements concerned<span>, like our bones and joints and heart and lungs) all were developed and conditioned </span>to figure within the<span> stronger gravity on </span>the surface<span>.</span>
5 0
4 years ago
Read 2 more answers
The green light emitted by a stoplight has a wavelength of 525 nm. What is the frequency of this photon? (c = 3.00 × 10⁸ m/s).
Reil [10]

The frequency of this photon is 5.94 x 10^{14} H_{Z}.

Solution:

The speed of light has a value of approximately <u>3.00×108 m/s</u>

The wavelength should have units of meters.

The frequency should have units of Hz or s−1. Hz is hertz or reciprocal seconds.

We know the value of the speed of light and we are given the wavelength. All we have to do is rearrange the equation to solve for the frequency:

<u>v = c/λ</u>

= 3.00×10^{8} m/s/505×10^{-9} m

= 5.94X10^{14}s-1

= <u>5.94X</u>10^{14}<u> Hz</u>

<u />

Frequency describes the number of waves passing through a particular location at a particular time. A class interval frequency is the number of observations that occur in a particular predefined interval. So, for example, if 20 of her ages 5-9 appear in the survey's data, the interval 5-9 has a frequency of 20. The class interval endpoints are the lowest and highest possible values ​​of the variable.

Learn more about The frequency here:- brainly.com/question/254161

#SPJ1

7 0
1 year ago
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