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3 years ago

Solve 10 - 3x = 2x - 8x + 20

Mathematics

2 answers:

Norma-Jean [14]3 years ago

7 0

$10 - 3x = 2x - 8x + 20\\
3x=10\\
x=\frac{10}{3}$

Dafna11 [192]3 years ago

5 0

$10-3x=2x-8x+20\\\\10-3x=-6x+20\ \ \ \ |subtract\ 10\ from\ both\ sides\\\\-3x=-6x+10\ \ \ \ |add\ 6x\ to\ both\ sides\\\\3x=10\ \ \ \ \ |divide\ both\ sides\ by\ 3\\\\x=\frac{10}{3}\\\\\boxed{x=3\frac{1}{3}}$

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faltersainse [42]

Hello,
We know that
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3 years ago

Fernando loves to make music playlists. He likes to keep the same ratio of country songs to rock songs. On his summer playlist,

Ede4ka [16]

Answer:

There are 6 rock songs on Fernando's road trip playlist.

Step-by-step explanation:

Given that he keeps the ratio same

This means that the ratios for both summer playlist and trip playlist will be the same

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Both will be equal so

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Putting the values

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Step-by-step explanation:

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Leni [432]

Answer:

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2 years ago

Ad is tangent to circle o at d. find ab. round to the nearest tenth if necessary

Naddik [55]

Check the picture below.

$\bf 0=AB^2+6AB-121\implies \stackrel{\textit{using the quadratic formula}}{AB=\cfrac{-6 \pm \sqrt{6^2-4(1)(-121)}}{2(1)}}
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AB=\cfrac{-6 \pm \sqrt{520}}{2}\implies AB=\cfrac{-6 \pm \sqrt{4\cdot 130}}{2}
\\\\\\
AB=\cfrac{-6 \pm \sqrt{2^2\cdot 130}}{2}\implies AB=\cfrac{-6 \pm 2\sqrt{130}}{2}
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\begin{cases}
\boxed{-3+\sqrt{130}}\\\\
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\end{cases}$

since the distance AB cannot be a negative value, thus is not -3-√(130).

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3 years ago

Read 2 more answers