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tekilochka [14]
3 years ago
15

A small rug is 36 inches long. It’s width is 2/3 of its length.what is the width of the rug in feet

Mathematics
2 answers:
ivanzaharov [21]3 years ago
8 0
24 inches

36 x 2/3 = 24
d1i1m1o1n [39]3 years ago
8 0

Answer:

24 inch width

Step-by-step explanation:

First you divide 36 by 3 to get 12

Then multiply 12 by 2 and get the answer;

24 inch width

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Volgvan

Answer:

The length side of the original square banner was 9 ft

Step-by-step explanation:

Let

x-----> the length side of the original square banner

we know that

The new area of the banner is equal to

91=(x+4)(x-2)

Solve for x

91=(x+4)(x-2)\\ \\91=x^{2}-2x+4x-8\\ \\x^{2}+2x-99=0

Solve the quadratic equation by graphing

The solution is x=9 ft

see the attached figure

8 0
3 years ago
Factor 4a2 - 25.<br><br> A. (2a + 5)(2a + 5)<br> B. (2a - 5)(2a - 5)<br> C. (2a - 5)(2a + 5)
nikdorinn [45]

This is the diference of 2 perfect squares. 4 is a perfect square, x^2 is a perfect square, and 25 is a perfect square. The pattern for this is (ax + b)(ax - b). Our a is 2 since 2*2 = 4, and our b is 5 since 5*5 = 25. So your factors are (2a+5)(2a-5), choice C.

3 0
3 years ago
School lunch costs $1.25 per day. If there are 21 school days
prohojiy [21]

Answer:

$26.25

Step-by-step explanation:

1.25 per day

21 days

1.25 × 21 = 26.25

3 0
2 years ago
Read 2 more answers
The surface area of this triangular pyramid, whose base and lateral faces are congruent equilateral triangles, is __ square inch
DedPeter [7]

Answer:

The surface area is equal to 390\ in^{2}

Step-by-step explanation:

The surface area of the triangular pyramid is equal to the area of its four triangular faces

so

In this problem

SA=4[\frac{1}{2}(b)(h)]

we have

b=15\ in

h=13\ in

substitute the values

SA=4[\frac{1}{2}(15)(13)]=390\ in^{2}

4 0
3 years ago
Read 2 more answers
Regis leans a 10-foot ladder against a wall. The base of the ladder makes a 65 angle with the ground.
hammer [34]

The distance, In feet, from the base of the ladder to the base of the wall is 4.2 ft.

He needs to move the ladder 0.1 ft closer to the base of the building.

The situation forms a right angle triangle.

<h3>Right angle triangle</h3>

Right angle triangle has one of its angles as 90 degrees. The sides and angle can be found using trigonometric ratios.

The length of the ladder is the hypotenuse of the triangle formed. Therefore, the distance, In feet, from the base of the ladder to the base of the wall can be calculated as follows;

cos 65° = adjacent / hypotenuse

cos 65° = d / 10

d = 10 × 0.42261826174

d = 4.22618261741

d = 4.2 ft

She needs to move the ladder so it reached a window 9.6 feet above the ground. Therefore, the distance from the base of the ladder and the wall is as follows;

cos 65 = d / 9.6

d = 9.6 × 0.42261826174

d = 4.05696

d = 4.1

Therefore, he needs to move the ladder 0.1 ft closer to the building.

learn more on right angle triangle here: brainly.com/question/14988069

8 0
2 years ago
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