Answer:
The perimeter of the kitchen wall = 60 b
Step-by-step explanation:
The number if tiles used in the length side of the square walk = 5 tiles
The length of 1 tiles = 3 b
So, the length of 5 tiles = 5 x ( Length of 1 tile)
= 5 x (3 b) = 15 b
So, the length of the square walk = 1 5 b
Perimeter of SQUARE = 4 x SIDES
⇒ Perimeter of the wall = 4 x (Side)
= 4 x (15 b) = 60 b
Hence, the perimeter of the kitchen wall = 60 b
Step-by-step explanation:
fifth row=19+4=23
sixth row= 23+4=27
Answer:
f) a[n] = -(-2)^n +2^n
g) a[n] = (1/2)((-2)^-n +2^-n)
Step-by-step explanation:
Both of these problems are solved in the same way. The characteristic equation comes from ...
a[n] -k²·a[n-2] = 0
Using a[n] = r^n, we have ...
r^n -k²r^(n-2) = 0
r^(n-2)(r² -k²) = 0
r² -k² = 0
r = ±k
a[n] = p·(-k)^n +q·k^n . . . . . . for some constants p and q
We find p and q from the initial conditions.
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f) k² = 4, so k = 2.
a[0] = 0 = p + q
a[1] = 4 = -2p +2q
Dividing the second equation by 2 and adding the first, we have ...
2 = 2q
q = 1
p = -1
The solution is a[n] = -(-2)^n +2^n.
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g) k² = 1/4, so k = 1/2.
a[0] = 1 = p + q
a[1] = 0 = -p/2 +q/2
Multiplying the first equation by 1/2 and adding the second, we get ...
1/2 = q
p = 1 -q = 1/2
Using k = 2^-1, we can write the solution as follows.
The solution is a[n] = (1/2)((-2)^-n +2^-n).
Answer: Width = 3cm
Length = 8cm
Step-by-step explanation:
Length = x+5 cm
Width = xcm
Area = 24cm²
Area of a rectangle = length × width
x × (x + 5) = 24
x² + 5x = 24
x² + 5x - 24 = 0
x² + 8x - 3x - 24 = 0
x(x + 8) - 3(x + 8) = 0
x - 3 = 0
x = 3
Width = 3cm
Since length = x + 5 = 3 + 5 = 8cm
Length = 8cm