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Len [333]
3 years ago
7

Solve the system of equation by elimination.

Mathematics
1 answer:
olya-2409 [2.1K]3 years ago
7 0
B.) no solution......
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The average score of those students who passed a test was 65, the average score of those who did not pass was 35, and the overal
FrozenT [24]

Answer:

60%

Step-by-step explanation:

To find the total pass = 65 * number of student that passed, let it be be represented by P and number of students that failed F

Total pass = 65p

And total fail = 35F

For the total pass and failure will be 53(P+F)

Equating to total pass and total fail

65P +35F = 53( P+ F)

65P+35F = 53P+ 53F

65P-53P =53F-35F

12P=18F

2P= 3F

Hence there are 3 passing scores for every 2 failure scores, hence there are a multiple of 5 scores and the same multiple of 3 passing scores.

3/5 * 100= 60%

4 0
3 years ago
Question 1
salantis [7]

Answer:

$384.00

Step-by-step explanation:

Since $8..0 is 1 hour, just multiply 48 x 8! Hope this helps!

4 0
3 years ago
Read 2 more answers
3.
irina1246 [14]
3)
Principal Amount = P = $7200
Interest rate = r = 4% = 0.04
Time = t = 8 years

Formula for compounding is:

A=P (1+r)^{t}

Using the values, we get:

A=7200 (1+0.04)^{8}=9853.70

Therefore, the compounded amount will be $9853.70 

4)
Principal Amount = P = $7200
Compounded Amount = A = $9853.70

Interest Earned = Compounded Amount - Principal Amount
So,
Interest Earned = 9853.70 - 7200 = $2653.70

Therefore, $2653.70 will be earned as interest over a period of 8 years.
5 0
3 years ago
Which of the following situations forms a proportional relationship? Select all that apply.
Schach [20]

Answer: 1st,2nd, and 4th one are correct.

Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
In a sample of 41 temperature readings taken from the freezer of a restaurant, the mean is 29.7 degrees and the population stand
yKpoI14uk [10]

Answer: =(29.1596\text{ degrees},\ 30.2404\text{ degrees})

Step-by-step explanation:

Given: Sample size: n = 41

Sample mean \overline{x}= 29.7 degrees

Population standard deviation \sigma=2.7 degrees

Confidence level (c) =  80% =0.80

Significance level (a) = 1- c = 1-0.80 = 0.20

z-score for 80% confidence level : z = 1.2816   [from z-table]

Confidence level for population mean :-

\overline{x}\pm z\dfrac{\sigma}{\sqrt{n}}

=29.7\pm ( 1.2816)\dfrac{2.7}{\sqrt{41}}

=29.7\pm ( 1.2816)\dfrac{2.7}{6.403124}

=29.7\pm ( 1.2816)(0.42167)

=29.7\pm 0.5404

=(29.7-0.5404,\ 29.7+0.5404)

=(29.1596,\ 30.2404)

Hence, 80% confidence interval for the temperatures in the freezer =(29.1596\text{ degrees},\ 30.2404\text{ degrees})

7 0
3 years ago
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