Consider the initial value problem 2ty′=4y, y(1)=−2. 2ty′=4y, y(1)=−2. find the value of the constant cc and the exponent rr so
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As here we are given with an equilateral triangle, whose side is 3 cm, and we need to find the height and area of the equilateral triangle. So, for this let's recall that, the area of any equilateral triangle with side a is given by ;
So, if we substitute a = 3, in our Formula, it will yield to
Now, as we know that, for any triangle we also have a formula that is ;
Now, Here as the triangle is equilateral, so it's base will just be same 3, and if we let height be H, so we will be having