If f(x) is a third degree polynomial function, how many distinct complex roots are possible?
2 answers:
Answer:
A: 0 or 2
Step-by-step explanation:
on edge
Answer:
0 or 2
Step-by-step explanation:
The Fundamental theorem of Algebra states that a polynomial of degree n has n roots.
Since degree 3 then there are 3 possible roots
Since complex roots occur in conjugate pairs then
There can be 0 or 2 complex roots.
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6.23+ -12.49 -2.6= 6.23+ -12.49+ -2.6
-6.26+-2.6= -8.86
Answer:
(x) = 4
Step-by-step explanation:
3/4 (x) + 4 = 7
3/4 (4) + 4 = 7
0.75 (4) + 4 = 7
3 + 4 = 7
7 = 7
190.18 is the average balance
4
Answer:
$1,747.75
Step-by-step explanation:
(12.7% = 0.127)
$2,002 x 0.127 = 254.25
$2,002 - 254.25 = $1,747.75
