If f(x) is a third degree polynomial function, how many distinct complex roots are possible?
2 answers:
Answer:
A: 0 or 2
Step-by-step explanation:
on edge
Answer:
0 or 2
Step-by-step explanation:
The Fundamental theorem of Algebra states that a polynomial of degree n has n roots.
Since degree 3 then there are 3 possible roots
Since complex roots occur in conjugate pairs then
There can be 0 or 2 complex roots.
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3:5 = x:20
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(Cross method)
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x =12
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Answer:
The answer is the 1st one
Step-by-step explanation:
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Answer:
2 is added
Step-by-step explanation:
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