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sveta [45]
3 years ago
8

If f(x) is a third degree polynomial function, how many distinct complex roots are possible?

Mathematics
2 answers:
seraphim [82]3 years ago
5 0

Answer:

A: 0 or 2

Step-by-step explanation:

on edge

monitta3 years ago
3 0

Answer:

0 or 2

Step-by-step explanation:

The Fundamental theorem of Algebra states that a polynomial of degree n has n roots.

Since degree 3 then there are 3 possible roots

Since complex roots occur in conjugate pairs then

There can be 0 or 2 complex roots.

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Round to the nearest whole number. Simplify (5(12 - 2)2 + 7]/3=
mario62 [17]

(5(12-2)2+7)/3

(5(10)2+7)/3

(50(2)+7)/3

(100+7)/3

107/3

35.66666...

<h2><em>36</em></h2>
7 0
3 years ago
A cube is wrapped with shrink wrap. How many square inches of shrink wrap are needed to wrap 5 cubes? Only enter the number part
viva [34]
Answer- 270

Find SA. SA=6(area of one face)
7 0
2 years ago
Write an equation of the line that passes through the given points.<br> (-1,7) and (4, -8)
djverab [1.8K]

Answer:

y=-3x+4

Step-by-step explanation:

m=(y2-y1)/(x2-x1)

m=(-8-7)/(4-(-1))

m=-15/(4+1)

m=-15/5

m=-3

y-y1=m(x-x1)

y-7=-3(x-(-1))

y-7=-3(x+1)

y=-3x-3+7

y=-3x+4

3 0
3 years ago
BRAINLIESTT ASAP! PLEASE HELP ME :)
Maslowich

Step-by-step explanation:

\displaystyle y = Asin(Bx - C) + D

According to this trigonometric function, −C gives you the OPPOSITE terms of what they really are, so be EXTREMELY CAREFUL:

\displaystyle Phase\:[Horisontal]\:Shift → \frac{0}{\frac{1}{7}} = 0 \\ Period → \frac{2}{1}π = 2π

Therefore we have our answer.

Extended Information on the trigonometric function

\displaystyle Vertical\:Shift → D \\ Phase\:[Horisontal]\:Shift → \frac{C}{B} \\ Period → \frac{2}{B}π \\ Amplitude → |A|

NOTE: Sometimes, your <em>vertical shift</em> might tell you to shift your graph below or above the <em>midline</em> where the amplitude is.

I am joyous to assist you anytime.

3 0
3 years ago
What’s the height of the can?
kondaur [170]

Answer:

5 inches

Step-by-step explanation:

The formula to find the surface area of a cylinder is A = 2πrh + 2πr²  

Since we need the height we will need to solve for h

  • First we can subtract 2πr² from both sides to get A - 2πr² = 2πrh
  • Then we can divide both sides by 2πr to get h=\frac{A-2\pi r^{2}  }{2\pi r}

Now we can plug in our known values and solve for h

  • Here we were given the diameter, d, however this formula is in terms of the radius, r.
  • The diameter is equivalent to double the radius, d = 2r
  • Therefore the radius is equivalent to half the diameter, r=\frac{1}{2} d
  • Plugging in d to solve for r we get r=\frac{1}{2}(2) which simplifies to r = 1

The two variables for this equation we have no obtained, A = 12π and r = 1, so we can plug them into our equation to solve for the height

  • h=\frac{12\pi -2\pi (1)^{2}  }{2\pi (1)}=h=\frac{12\pi -2\pi  }{2\pi }=\frac{10\pi }{2\pi } =5
  • The height is 5 inches
4 0
3 years ago
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