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sveta [45]
3 years ago
8

If f(x) is a third degree polynomial function, how many distinct complex roots are possible?

Mathematics
2 answers:
seraphim [82]3 years ago
5 0

Answer:

A: 0 or 2

Step-by-step explanation:

on edge

monitta3 years ago
3 0

Answer:

0 or 2

Step-by-step explanation:

The Fundamental theorem of Algebra states that a polynomial of degree n has n roots.

Since degree 3 then there are 3 possible roots

Since complex roots occur in conjugate pairs then

There can be 0 or 2 complex roots.

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2 Points
KonstantinChe [14]

Answer:

C

Step-by-step explanation:

The angle adjacent to x on XY = 115° ( corresponding angle )

This angle and x are adjacent and supplementary , thus

x = 180 - 115 = 65 → C

6 0
3 years ago
Read 2 more answers
You volunteer to help drive children at a charity event to the zoo, but you can fit only 7 of the 18 children present in your va
yulyashka [42]

The answer is 19,448 different groups, using the formula from permutation and combinations C (n, r) = (n!) / (r! (n-r)!) which calculates the number of times where r objects can be chosen from n object.

So,

C (17,7) = (17!) / (7! *(17-7)!)

C (17,7) = (17!) / (7! *10!)

C (17,7) = (17*16*15*14*13*12*11*10!) / (7! *10!) then eliminate 10!

C (17,7) = (17*16*15*14*13*12*11) / (7*6*5*4*3*2*1) = (98017920)(5040)

C (17,7) = 19,448 different groups

3 0
4 years ago
PLEASE ANSWER WILL MARK BRAINLIEST AND ALL OF THAT
juin [17]
5 is the answer



hope i helped

3 0
3 years ago
Read 2 more answers
Richardo had saved $80 from his summer job to buy video games. He
Vlad1618 [11]

Answer:

$15.90

Step-by-step explanation:

80 - 16.40 = 63.60

63.60÷4 =15.9

15.9 = $15.90

7 0
3 years ago
PLZ HELP ASAP !!! 25 POINTS !!!
jolli1 [7]

the first picture number 1 is a function

the second one the third one

but I'm not sure

7 0
3 years ago
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