M = y2-y1/x2-x1
= 2 - 3 / 0 - 1
= -1 / -1
= 1
Y = x + b
2 = 0 + b
2 = b
Y = x + 2
0 = x - y + 2
-2 = x - y
2 = -x + y
Therefore, the equation of the line in standard form is 2 = -x + y
(not sure if done right lol)
Answer:
The student whose marks between quarter grades & topic tests score has maximum proportionate deviation
Step-by-step explanation:
Percentage change shows the proportionate change in a value, from the initial point. Formula = ( Change / Old ) x 100
Percentage change in students' quarter grades from topic tests score =
[ ( Quarter topic test score - Topic test score ) / Topic Test score ] x 100
Eg : Quarter Grade = 80, Test score = 60.
Percentage change = [ (80 - 60)/ 60 ] x 100 = ( 20 / 60 ) x 100 = 33%
So, student who has this maximum proportionate or percentage deviation between quarter grades & topic tests score - that student change would be represented by the point farthest from 0 on a number line.
-0.85 as a fraction is -17/20.
Answer:I believe it's y=log(x-3)
Step-by-step explanation:
