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umka2103 [35]
3 years ago
7

If 2+root3/2-root/3 + 2-root3/2+root3 =a+b root3 find the values of a and b

Mathematics
1 answer:
andreyandreev [35.5K]3 years ago
5 0
To solve for 2 variables, you need 2 equations. The best you could do with only one equation would be to find 'a' in terms of 'b'. Just looking it over and without putting pen to paper, it looks to me like one possible solution is [ a = 4, b = 0 ].
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Out of a salary of $4500. I kept 1/3 as saving. Out of the remaining money. I spend 50% on food and 20% on house rent. How much
Step2247 [10]
Well 1/3 for savings means that you save 1/3*4500 or 1500 dollars.
You then have $3000 left. Of this if you spend 50% on food, you spend 0.5*3000 or 1500 dollars on food.
7 0
3 years ago
Can I please get help with this question please?
solmaris [256]

what are the choices?


6 0
2 years ago
Read 2 more answers
MARSVECTORCALC6 3.4.020. My Notes A rectangular box with no top is to have a surface area of 64 m2. Find the dimensions (in m) t
ioda

Answer:

We would have

                                    l =w =\frac{8\sqrt{3}}{3} \\h = \frac{8\sqrt{3}}{6}

where " l " is  length, " w"  is width and "h" is height.

Step-by-step explanation:

Step 1

Remember that

         Surface area for a box with no top = lw+2lh+2wh = 64

where " l " is  length, " w"  is width and "h" is height.

 Step 2.

Remember as well that

                              Volume of the box = l*w*h

Step 3

 We can now use lagrange multipliers.  Lets say,

                                    F(l,w,h) = lwh

and

                                g(l,w,h) = lw+2lh+2wh = 64

By the lagrange multipliers method we know that                            

 

                                                     \nabla F  = \lambda \nabla g

Step 4

Remember that

                          \nabla F  = (wh,lh,lw)

and

                      \nabla g = (w+2h,l+2h , 2w+2l)

So basically you will have the system of equations

                              wh = \lambda (w+2h)\\lh = \lambda (l+2h)\\lw = \lambda (2w+2l)

Now, remember that you can multiply the first eqation, by "l" the second equation by "w" and the third one by "h" and you would get

                                   lwh = l\lambda (w+2h)\\\\lwh = w\lambda (l+2h)\\\\lwh = h\lambda (2w+2l)

Then you would get

                      l\lambda (w+2h) = w\lambda (l+2h) =  h\lambda (2w+2l)

You can get rid of \lambda from these equations and you would get

                         lw+2lh = lw+2wh =  2wh+2lh

And from those equations you would get

                                             l = w =2h

Now remember the original equation

                                    lw+2lh+2wh = 64

If we plug in what we just got, we would have

                                 l^{2} + l^{2} + l^2   =  64 \\3l^{2} = 64 \\l = w = \frac{8\sqrt{3} }{3} \\h = \frac{8\sqrt{3} }{6}

                       

                                                 

7 0
3 years ago
A patient ingests 5 grams of a certain drug which
IgorC [24]

Answer:

8 hours

Step-by-step explanation:

5 - 1 = 4 grams

10% of 5 = 0.5 grams per hour

4/0.5 = 8 hours

8 0
2 years ago
How many times does 7 and 9 go on to 27
const2013 [10]

Answer:

they both go into 27 3 times

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
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