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AleksandrR [38]
3 years ago
12

What are the possible values of x if (4x – 5)2 = 49? Check all that apply. StartFraction negative 4 Over 5 EndFraction StartFrac

tion negative 1 Over 2 EndFraction 3 5 7
Mathematics
2 answers:
kkurt [141]3 years ago
7 0

(4x - 5)^2 = 49\\x = 3, -\frac{1}{2}

⭐ Please consider brainliest! ⭐

✉️ If any further questions, inbox me! ✉️

puteri [66]3 years ago
7 0

Answer:

Option 2 and 3 - 3 and -\frac{1}{2}

Step-by-step explanation:

Given : Equation (4x-5)^2=49

To find : What are the possible values of x ?

Solution :

Equation (4x-5)^2=49

Taking root both side,

\sqrt{(4x-5)^2}=\sqrt{49}

(4x-5)=\pm 7

Taking 4x-5=7

4x=7+5

4x=12

x=\frac{12}{4}

x=3

Taking 4x-5=-7

4x=-7+5

4x=-2

x=-\frac{2}{4}

x=-\frac{1}{2}

The possible values of x are 3 and -\frac{1}{2}

Therefore, option 2 and 3 are correct.

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vovikov84 [41]

Answer:

The simplified expression to the given expression is \frac{4x^6}{y^2}

Therefore \frac{4(2x^3y^4)^4}{2(2x^2y^6)^3}=\frac{4x^6}{y^2}

Step-by-step explanation:

Given fractional expression is \frac{4(2x^3y^4)^4}{2(2x^2y^6)^3}

To simplify the given expression as below :

\frac{4(2x^3y^4)^4}{2(2x^2y^6)^3}

=\frac{2(2x^3y^4)^4}{(2x^2y^6)^3}

=\frac{2[(2)^4(x^3)^4(y^4)^4]}{(2)^3(x^2)^3(y^6)^3}  ( using the property (a^m)^n=a^{mn})

=\frac{2[(2)^4(x^{12})(y^{16})]}{(2)^3(x^6)(y^{18})}

=2[(2)^4(x^{12})(y^{16})](2)^{-3}(x^{-6})(y^{-18})  (  ( using the property a^m=\frac{1}{a^{-m}} )

=2[2^{4-3}x^{12-6}y^{16-18}]( using the property a^m.a^n=a^{m+n} )

=2[2^1x^6y^{-2}]

=\frac{4x^6}{y^2} ( using the property a^m=\frac{1}{a^{-m}} )

Therefore the simplified expression is \frac{4x^6}{y^2}

Therefore \frac{4(2x^3y^4)^4}{2(2x^2y^6)^3}=\frac{4x^6}{y^2}

5 0
3 years ago
PICTURES BELOW!!! PLEASE HELP!! XTRA POINTS TO CORRECT ANSWER!!!
Archy [21]

Answer:

The second graph

Step-by-step explanation:

take x = 3 for instance, we can see that on the graph both lines intersect on y = 8

if we try it with our equations:

-2 * 3 + 14 = 8

2 * 3 + 2 = 8

Hope thi helps, please give brainliest thanks

3 0
3 years ago
Find Ms. Buggie's mistake in the following problem. Then, give what the correct answer should be.
sdas [7]

Answer:

Mrs. Buggie should have Subtracted 13 instead of adding 13

LKA = 94°

Step-by-step explanation:

Lets work backwards from the equation so far:

40 = x+ 13

x + 13 = 40

We should subtract 13 because we are adding a number and 13 to 40

Imagine this:

You have 5 apples, but you bought some more and now you have 10

equation would be:

5+x = 10

subtract 5 from 10 to get 5

So you bought 5 apples

Back to the Question:

40 - 13 = 27

3(27) + 13 = 81+13 = 94°

Answer = 94°

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-Chetan K

8 0
3 years ago
Ruby conducted a survey and found the 5/6 of her classmates have a pet and 2/3 of those pets are dogs.what fraction of her class
Pie
To determine the fraction of her classmates with dogs as pets, we simply multiply the two given fractions based from the survey. 

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Thus, there are 5/9 of Ruby;s car. 
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4 years ago
I need help on this. The portrait studio can buy photographs on canvas. The small canvas photograph print is $20 and the large c
Whitepunk [10]
<h3>Answer:</h3>
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<h3>Step-by-step explanation:</h3>

<em>Numerical Reasoning</em>

Consider a set of prints that consists of 2 small prints and one large print (that is, twice as many small prints as large). The value of that set will be ...

... 2×$20 +45 = $85

To have revenue of at least $510, the studio must sell ...

... $510/$85 = 6

sets of prints. That is, the studio needs to sell at least 6 large prints and 12 small ones.

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<em>With an equation</em>

Let x represent the number of large prints the studio needs to sell. Then 2x will represent the number of small prints. Total sales will be ...

... 20·2x +45·x ≥ 510

... 85x ≥ 510

... x ≥ 510/85

... x ≥ 6

The studio needs to sell at least 6 large prints and 12 small prints.

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