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AleksandrR [38]
3 years ago
12

What are the possible values of x if (4x – 5)2 = 49? Check all that apply. StartFraction negative 4 Over 5 EndFraction StartFrac

tion negative 1 Over 2 EndFraction 3 5 7
Mathematics
2 answers:
kkurt [141]3 years ago
7 0

(4x - 5)^2 = 49\\x = 3, -\frac{1}{2}

⭐ Please consider brainliest! ⭐

✉️ If any further questions, inbox me! ✉️

puteri [66]3 years ago
7 0

Answer:

Option 2 and 3 - 3 and -\frac{1}{2}

Step-by-step explanation:

Given : Equation (4x-5)^2=49

To find : What are the possible values of x ?

Solution :

Equation (4x-5)^2=49

Taking root both side,

\sqrt{(4x-5)^2}=\sqrt{49}

(4x-5)=\pm 7

Taking 4x-5=7

4x=7+5

4x=12

x=\frac{12}{4}

x=3

Taking 4x-5=-7

4x=-7+5

4x=-2

x=-\frac{2}{4}

x=-\frac{1}{2}

The possible values of x are 3 and -\frac{1}{2}

Therefore, option 2 and 3 are correct.

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