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Reika [66]
2 years ago
11

A boy saves 80p a day, How much does it take him to save $40

Mathematics
1 answer:
laiz [17]2 years ago
8 0

Answer:

50 Days

Step-by-step explanation:

I'm not sure what the unit "p" is, but I believe it is pennies so. $40/0.80 gives you 50 which is the amount of days it would take for you to get to $40 if you receive 80 cents a day

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using the standard form ax^2+bx+c=0 of the given quadratic equation, factor the left hand side of the equation into two linear f
Galina-37 [17]

Answer:

See below

Step-by-step explanation:

Since you didn't give an actual quadratic equation and just the standard form equation, I will reduce ax^2+bx+c=0:

(ax+p)(x+q) where p+q=b and pq=c

5 0
3 years ago
Nine tiles are numbered $\color[rgb]{0.35,0.35,0.35}1, 2, 3, \ldots, 9$. Each of three players randomly selects and keeps three
Eduardwww [97]

The probability that all three players obtain an odd sum is 3/14.

<h3>What is probability?</h3>

The probability is the ratio of possible distributions to the total distributions.

I.e.,

Probability = (possible distributions)/(total distributions)

<h3>Calculation:</h3>

Given that,

There are nine tiles - 1, 2, 3,...9, respectively.

A player must have an odd number of odd tiles to get an odd sum. That means he can either have three odd tiles, or two even tiles and an odd tile.

In the given nine tiles the number of odd tiles = 5 and the number of even tiles = 4.

The only possibility is that one player gets 3 odd tiles and the other two players get 2 even tiles and 1 odd tile.

So,

One player can be selected in ^3C_1  ways.

The 3 odd tiles out of 5 can be selected in ^5C_3 ways.

The remaining 2 odd tiles can be selected and distributed in ^2C_1 ways.

The remaining 4 even tiles can be equally distributed in \frac{4 ! \cdot 2 !}{(2 !)^{2} \cdot 2 !} ways.

So, the possible distributions = ^3C_1 × ^5C_3 × ^2C_1 × \frac{4 ! \cdot 2 !}{(2 !)^{2} \cdot 2 !}

⇒ 3 × 10 × 2 × 6 = 360

To find the total distributions,

The first player needs 3 tiles from the 9 tiles in ^9C3=84 ways

The second player needs 3 tiles from the remaining 6 tiles in ^6C_3=20 ways

The third player takes the remaining tiles in 1 way.

So, the total distributions = 84 × 20 × 1 = 1680

Therefore, the required probability = (possible distributions)/(total distributions)

⇒ Probability = 360/1680 = 3/14.

So, the required probability for the three players to obtain an odd sum is 3/14.

Learn more about the probability of distributions here:

brainly.com/question/2500166

#SPJ4

3 0
1 year ago
12^1/2(2^1/2+3^1/2)(2^1/2-3^1/2)
krek1111 [17]
I don’t understand where is the equation
4 0
3 years ago
Read 2 more answers
What is the length of the hypotenuse in the right triangle shown below?<br>​
Eduardwww [97]

Answer:

C.  6√2.

Step-by-step explanation:

Since this is a right angled isosceles triangle bot legs are 6 units long

So h^2 = 6^2 + 6^2 = 72

h = √72 = 6√2.

7 0
3 years ago
Read 2 more answers
PLEASE SOMEONE BLESS UP AND HELPPP MEEEE AND ILL MARK YOU BRAINLIEST THANKSSSS
Assoli18 [71]
It’s t20=20

I am doing the same thing in math
8 0
3 years ago
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