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sleet_krkn [62]
3 years ago
9

Triangle A is a scaled version of triangle B. The dimensions of triangle A are three times the dimensions of triangle B. The are

a of triangle A is 54 sq cm.
Mathematics
1 answer:
inessss [21]3 years ago
6 0
9 * 12 = 108
the base is 9 and the height is 12
now the formula for the area of a triangle is 1/2 *(b)*(h)

multiply 9 * 3 = 27
multiply 12 * 3 = 36

multiply base = 27 * height = 36 
27 * 36 = 972
now divide that by 2
486 sq cm.
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I need help please and thank you
Margarita [4]

The sum of the angles of a triangle is 180°.

The angles you know are 28° and 36°, so you can do this to find ∠B:

∠A + ∠B + ∠C = 180°

or 28° + ∠B + 36° = 180°      Add 28 and 36

64° + ∠B = 180°      Subtract 64 on both sides

∠B = 116

3 0
3 years ago
Identify the area of the trapezoid. options: 299cm^2 325cm^2 425cm^2 399cm^2
shtirl [24]

Answer:399

Step-by-step explanation:

((a+b)/2) * h

((13+25)/2) * 21

399

<!> Brainliest is appreciated! <!>

8 0
4 years ago
Read 2 more answers
At another sanctuary, the number of nesting turtles decreased by 10%. This year there were 234 nesting turtles. How many nesting
Alex

Answer:

260 nesting turtles were at this sanctuary last year

Step-by-step explanation:

Given:

The number of nesting turtles decreased = 10%

Number of turtles  present in sanctuary this year = 234

To Find:

Number of nesting turtles present at this sanctuary last year= ?

Solution:

Let the number of nesting turtles present at this sanctuary last year be x

Then,

x- 10% of x = Number of turtles  present in sanctuary this year

x- 10% of x = 234

x- (\frac{10}{100} \times x) = 234

x- (\frac{1}{10} \times x) = 234

x- (\frac{x}{10}) = 234

\frac{10x-x}{10}=234

\frac{9x}{10}=234

9x=234\times 10

9x=2340

x=\frac{2340}{9}

x= 260

7 0
3 years ago
What is the difference between 4/5 and 3/8
ziro4ka [17]
The difference is 4/5 - 3/8 = 17/40
6 0
3 years ago
Read 2 more answers
PLEASE HELP &amp; SHOW WORK , ITS URGENT
ValentinkaMS [17]

Answer:

D. 80 ft

substitute known values into the equation for area

8 0
3 years ago
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