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xz_007 [3.2K]
3 years ago
12

A student considers how mnay people enter a particular bank during the lunch hour and how many exit. She decided to run a simula

tion. She assigns the value 0 to represent a person entering the bank and 1 to represent a person exciting the bank. Based on a simulation fot the first 20 people she observes, estimate the probability she will see a person entering the bank.
0 1 0 0 0 1 1 1 0 1 0 0 0 1 0 1 0 0 1 0

0.400
0.250
0.500
0.600
Mathematics
2 answers:
german3 years ago
8 0

Answer:

0.600

Step-by-step explanation:

gradpoint

trapecia [35]3 years ago
3 0

Answer:

The number of persons entering the bank based on given 20 simulations are 12

The number of persons exiting the bank based on given 20 simulations are 8

We have to find the probability that she will see a person entering the bank.

The probability that she will see a person entering the bank is:

\frac{12}{20}

0.6

Therefore, the option 0.600 is correct.


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Josh has a box of ballons.in that box he finds that 1/8 of the ballons are blue out of 120 ballons in the box the rest is red.ho
Stolb23 [73]

Answer:

15

Step-by-step explanation:

1/8 times 120= 15

5 0
2 years ago
The rectangle below has an area of x² – 6x – 7 square meters and a width of 3 – 7 meters.
natta225 [31]

Answer:

The expression which represent the length of the rectangle is x + 1

Step-by-step explanation:

Given as :

The Area of rectangle = x² - 6 x - 7  square meters

The width of the rectangle = w = x - 7 meters

Let The length of rectangle = L meters

Now, <u>According to question</u>

∵ Area of Rectangle = Length × width

or, x² - 6 x - 7  meters² = L meters × w meters

or, x² - 6 x - 7 = L × (x - 7)

or, x² - 7 x + x - 7 = L × (x - 7)

or, x (x - 7) + 1 (x - 7) = L × (x - 7)

or, (x - 7) (x + 1) = L × (x - 7)

∴ L = \frac{(x - 7)\times (x + 1)}{(x - 7)}

I,e L = x + 1

So, The length of rectangle = L = x + 1

Hence,The expression which represent the length of the rectangle is x + 1 Answer

8 0
2 years ago
Show that if u+v and u-v are orthognal, then the vectors u and v must have the same length.
pashok25 [27]

Answer with Step-by-step explanation:

We are given that

u+ v and u-v are orthogonal

We have to prove that u and v must have the same length.

When two vector a and b are orthogonal then

a\cdot b=0

By using the property

(u+v)\cdot (u-v)=0

We know that

(a+b)\cdot (a-b)=\mid a\mid^2-\mid b\mid^2

\mid u\mid ^2-\mid v\mid^2=0

\mid u\mid^2=\mid v\mid^2

Magnitude is always positive

When power of base on both sides are equal then base will be equal

Therefore,

\mid u\mid=\mid v\mid

Hence, the length of vectors u and v must have the same length.

5 0
3 years ago
Is this a function ? Yes or no and why or why not
never [62]

Answer:

Yes

Step-by-step explanation:

Yes it is a function, because graph is intersecting y - axis only once.

3 0
3 years ago
Y varies directly with x, and y = 5 when x = 4. What is the value of x when y = 8?
Tomtit [17]
As y varies directly with x, there is a proportionality constant. As x increases by that certain constant, y also increases. We equate:
y = kx
where k = proportionality constant.
Given the condition, y = 5 when x = 4, then we solve for k:
5 = k(4)
k = 5/4 or 1.25
When y = 8, then
8 = (5/4)(x)
x = 8/(5/4) = (8)(4/5) = 32/5 or 6.4 (ANSWER)
7 0
3 years ago
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