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xz_007 [3.2K]
3 years ago
12

A student considers how mnay people enter a particular bank during the lunch hour and how many exit. She decided to run a simula

tion. She assigns the value 0 to represent a person entering the bank and 1 to represent a person exciting the bank. Based on a simulation fot the first 20 people she observes, estimate the probability she will see a person entering the bank.
0 1 0 0 0 1 1 1 0 1 0 0 0 1 0 1 0 0 1 0

0.400
0.250
0.500
0.600
Mathematics
2 answers:
german3 years ago
8 0

Answer:

0.600

Step-by-step explanation:

gradpoint

trapecia [35]3 years ago
3 0

Answer:

The number of persons entering the bank based on given 20 simulations are 12

The number of persons exiting the bank based on given 20 simulations are 8

We have to find the probability that she will see a person entering the bank.

The probability that she will see a person entering the bank is:

\frac{12}{20}

0.6

Therefore, the option 0.600 is correct.


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You are considering buying organic milk at the grocery store. A gallon of organic milk costs $1.00 more than a regular gallon of
BARSIC [14]

Answer:

C= $1t + x

Step-by-step explanation:

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But then buying the organic milk over time is t so you add that to the one dollar since it applies to the organic milk. Now the equation is $1t + x.

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3 years ago
Find x helpppppppppppp​
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|2x - 1|  =  | - x - 2|

Thus ;

2x - 1 =  - x - 2

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2x + x - 1 =  - x + x - 2

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3x =   - 1

Divide both sides by 3

\frac{3x}{3}  =  \frac{ - 1}{3}  \\

x =  -  \frac{1}{3}  \\

<h2>Or </h2>

2x - 1 =  - ( - x - 2)

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3 0
2 years ago
Help me. I don't understand. Please help me find X and IK
sertanlavr [38]

Answer:

x=4\\\\y=6\\\\IK=47

Step-by-step explanation:

Two Tangent Theorem: Tangents which meet at same point are equal in length.

Here tangents at J and H meet at I.

Hence\ HI=IJ\\\\y^2-10=4y+2\\\\y^2-4y-12=0\\\\y^2-6y+2y-12=0\\\\y(y-6)+2(y-6)=0\\\\(y-6)(y+2)\\\\y\ can\ not\ be\ negative\ as\ in\ that\ case\ IJ\ will\ be\ negative.\\\\Hence\ y=6\\\\IJ=4y+2=4\times 6+2=26\\\\\\\\Tangents\ at\ J\ and\ L\ meet\ at\ K.\ Use\ two\ tangent\ theorem.\\\\JK=KL\\\\5x+1=6x-3\\\\6x-5x=1+3\\\\x=4\\\\JK=5x+1=5\times 4+1=21\\\\\\IK=IJ+JK=26+21\\\\IK=47

6 0
4 years ago
Find the sum of the first 20 terms of an arithmetic sequence with an 18th term of 8.1 and a common difference of 0.25.
il63 [147K]

The sum of the first 20 terms of an arithmetic sequence with the 18th term of 8.1 and a common difference of 0.25 is 124.5

Given,

18th term of an arithmetic sequence = 8.1

Common difference = d = 0.25.

<h3>What is an arithmetic sequence?</h3>

The sequence in which the difference between the consecutive term is constant.

The nth term is denoted by:

a_n = a + ( n - 1 ) d

The sum of an arithmetic sequence:

S_n = n/2 [ 2a + ( n - 1 ) d ]

Find the 18th term of the sequence.

18th term = 8.1

d = 0.25

8.1 = a + ( 18 - 1 ) 0.25

8.1 = a + 17 x 0.25

8.1 = a + 4.25

a = 8.1 - 4.25

a = 3.85

Find the sum of 20 terms.

S_20 = 20 / 2 [ 2 x 3.85 + ( 20 - 1 ) 0.25 ]

         = 10 [ 7.7 + 19 x 0.25 ]

         = 10 [ 7.7 + 4.75 ]

         = 10 x 12.45

         = 124.5

Thus the sum of the first 20 terms of an arithmetic sequence with the 18th term of 8.1 and a common difference of 0.25 is 124.5

Learn more about arithmetic sequence here:

brainly.com/question/25749583

#SPJ1

8 0
1 year ago
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