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4 years ago

8

A slide 4.1 meters long makes an angle of 35º with the ground. To the nearest tenth of a meter, how far above the ground is the

top of the slide?

1 answer:

Step2247 [10]4 years ago

4 0

length of the slide is lets say 'l' the height (h) opposite to the angle 28 is found by h=l*sin28 where sin28=0.47 approximately h=4.5*0.47 h=2.115m

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koban [17]

Answer: It would be 4b+44

Step-by-step explanation:

This is the distributive property! so a(b+c)=ab+ac

In this case–4b+44!

6 0

2 years ago

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I got 2 questions.

alexandr402 [8]

Answer:

1. In triangle ABC,

AC = a = 10, BC =b= 7 and ∠ C = 90°

By cosine law,

$AB^2 = 7^2 + 10^2 - 2\times 7\times 10 cos 90^{\circ}$

$AB^2 = 49 + 100 - 0$

$AB^2 = 149$

$AB= \sqrt{149}$

Now, by the law of sine,

$\frac{sin B}{10} = \frac{sin90^{\circ}}{\sqrt{149} }$

$sin B = \frac{10}{\sqrt{149} }$

$\angle B = 55.0079798014\approx 55.008^{\circ}$

2. In triangle ABC,

∠B = 30°, AB=c=10 and ∠C = 90°

∠A = 180°-(30+90)°=60°

$\frac{AC}{10}=sin30^{\circ}$

⇒ $AC = \frac{10}{2} = 5$

By Pythagoras,

$CB^2 = AB^2 - AC^2=10^2 - 5^2 = 100 - 25 = 75$

⇒ $CB = \sqrt{75} =8.66025403784\approx 8.66$

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4 years ago

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To rent a certain meeting room, a college charges a reservation fee of $46 and an additional fee of $6.70 per hour. The chemistr

atroni [7]

79.50 = 46 + 6.70t

33.50 = 6.70 t

t = 5 hours

3 0

2 years ago

Can someone please help?

Alekssandra [29.7K]

Answer:

g

Step-by-step explanation:

5 0

3 years ago

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A statistics teacher started class one day by drawing the names of 10 students out of a hat and asked them to do as many pushups

mash [69]

Using the t-distribution, we have that the 95% confidence interval for the true mean number of pushups that can be done is (9, 21).

For this problem, we have the <u>standard deviation for the sample</u>, thus, the t-distribution is used.

The sample mean is of 15, thus $\overline{x} = 15$ .
The sample standard deviation is of 9, thus $s = 9$ .
The sample size is of 10, thus $n = 10$ .

First, we find the number of degrees of freedom, which is the one less than the sample size, thus df = 9.

Then, looking at the t-table or using a calculator, we find the critical value for a 95% confidence interval, with 9 df, thus t = 2.2622.

The margin of error is of:

$M = t\frac{s}{n}$

Then:

$M = 2.2622\frac{9}{\sqrt{10}} = 6$

The confidence interval is:

$\overline{x} \pm M$

Then

$\overline{x} - M = 15 - 6 = 9$

$\overline{x} + M = 15 + 6 = 21$

The confidence interval is (9, 21).

A similar problem is given at brainly.com/question/25157574

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3 years ago