Based on the distance of the pitcher's mound from the home plate, the path of the ball, and the height the ball was hit, the distance the outfielder threw the ball is C. 183.0 ft.
<h3>How far did the outfielder throw the ball?</h3>
Based on the shape of a mound, the law of cosines can be used.
The distance the ball was thrown by the outfielder can therefore be d.
Distance is:
d² = 60.5² + 226² - (2 x 60.5 x 226 x Cos(39))
d ²= 33,484.42ft
Then find the square root:
d = √33,484.42
= 182.9874
= 183 ft
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Answer:
x=1056.25
Step-by-step explanation:
(2x)(2x)(55)=(65)(65)(55) Multiply
4x(55)=232375 Divide 55 from each side
4x=4225 Divide each side by 4
x=1056.25
Answer:
18 and 5
Step-by-step explanation:
if 'x' - is the length and 'y' - the width of the rectangle, then
2(x+y)=46 - perimeter of the original rectangle and 2(2x+(y+5))=66 - the perimeter of the new rectangle.
Finally, the length is x=5 and the width is y=18.
Answer:
Yes and b = why an no
Step-by-step explanation:
with thing and b
Answer:
this is the answer unless you did it backwards
Step-by-step explanation:
3.467406380027739e-4
